The answer is Contact force
Answer:
<h3>F = 35.84N</h3>
Explanation:
Force = mass * acceleration (Newton's second law of motion)
Given
Mass = 32kg
Get the acceleration using the expression d = 1/2at^2
3.5 = 1/2 (a)2.5^2
3.5 = 3.125a
a = 3.5/3.125
a = 1.12m/s^2
Get the net force;
F = 3.2 * 1.12
F = 35.84N
Hence the net force used to accelerate is 35.84N
By the work energy theorem, the total work done on the stone is given by its change in kinetic energy,
We have
Then the total work is
Answer:IM SORRY BUT I D K BUT I HOPE THAT YOU HAVE BETTER DAY AND REALAX AND THINK OF HAPPY THOUGHTS :D
Explanation:IM HE MYSTERY MAN WHOOSH??????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????
To solve the problem, we can use Kepler's third law, which states that the ratio between the square of the orbital period and the cube of the radius of the orbit is constant. So, we can rewrite it as follows:
where T are the periods, R the radius of the orbits (so, the distance of the satellites from Jupiter), and where the label c refers to Callisto and i to Io.
The problem says that the distance of Callisto from Jupiter is 4.5 times the distance of Io from Jupiter, i.e.:
If we substitute this into the previous equation, we can find a relationship between the two orbital periods Tc and Ti:
and so we have
that we can rewrite as
so, the orbital period of Callisto is 9.5 times the orbital period of Io.