I'm going too hell for putting answers that are not really good enough for you but I need my answers and I need help with my answers
Answer:
Temperature -SI unit :Kelvin
Explanation:
Kelvin is the SI unit of Temperature .
- Don't get confused and write Celsius as the SI unit .Celsius is not the SI unit .
Or
Lets take an example :-
Lets convert to Kelvin scale
- SI unit of Mass=kilogram(Kg)
- SI unit of Time=second(s)
- SI unit of electric current=Ampere(A)
Answer:
Explanation:
2 )
power of an electric device = V² / R where V is volts and R is resistance
putting given data
power = 9²/ 5
= 16.2 J/s
energy produced in 7 minutes
= 16.2 x 7 x 60
= 6804J .
3 ) Power of an electrical device
= V² / R
= V X I where I is current
= 4.5 x .5
= 2.25 W or J/s
4 )
energy used in 3 minutes with power of 2.25 W
= 2.25 x 3 x 60
= 405 J .
7 )
power of a electrical device
= V x I
IR x I where R is resistance .
= I²R
putting given data
power = .005² x 50
= 1.25 x 10⁻³ W .
8 )
Energy used up by a 60 W bulb in 2.5 hours
= 60 x 2.5 x 60 x 60
= 5.4 x 10⁵ J .
Answer:
D. You would weigh the same on both planets because their masses
and the distance to their centers of gravity are the same.
Explanation:
The above statement is true due to the fact that, the weight and masses of the individual are same in direct comparison with the distance to their center of gravity.<em> If the weight and masses are not same, then there would have been a significant difference between the two planet.</em>
Answer:
D. is always perpendicular to the surface of the conductor
Explanation:
1) Answer is (D) option. Electric field just outside surface of charged conductor is normal to conductor at that point.
It can be explained on the basis of the fact that, Electric field inside conductor under static condition is zero. As a result potential difference between any two points with in conductor is zero. So whole of conductor is equipotential body.
Equipotential surface and Electric field lines always cut at 90 degrees to each other. Conductor being equipotential body, Electric field lines starting or terminating at conductor must be normal to surface. Hence electric field just outside conductor is perpendicular or normal to surface.
