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prisoha [69]
3 years ago
15

You are the design engineer in charge of testing the crashworthiness of new automobile models. Cars are tested by smashing them

into fixed, massive barriers at 50 km/h (30 mph). A new model of mass 1500 kg takes 0.15 s from the time of impact until it is brought to rest. Take the initial velocity of the car to be positive. (A) Calculate the average force exerted on the car by the barrier.
Physics
1 answer:
BaLLatris [955]3 years ago
3 0

Answer:

average force  is 138900 N

Explanation:

given data

speed = 50 km/h = 13.89 m/s

mass = 1500 kg

time = 0.15 s

to find out

average force

solution

we know initial velocity of car is positive

we will apply here equation to find force that is

Force x change in time that is equal to  mass x change in speed    ................1

so put here all value of mass, time and velocity in equation 1

Force x 0.15 =  1500 x ( -13.89)

force = 138900 N

so average force  is 138900 N

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The resistor potential is constant and the inductor emf increases. The resistor potential is constant and the inductor emf decre
maks197457 [2]

The question is incomplete, the complete question is

When an RL circuit is connected to a battery, what happens to the potential difference across the resistor and the emf across the inductor?

The resistor potential is constant and the inductor emf increases.

The resistor potential is constant and the inductor emf decreases.

The resistor potential is constant and the inductor emf is constant.

The resistor potential decreases and the inductor emf is constant.

The resistor potential decreases and the inductor emf increases.

The resistor potential decreases and the inductor emf decreases.

The resistor potential increases and the inductor emf increases.

The resistor potential increases and the inductor emf is constant.

The resistor potential increases and the inductor emf decreases.

Answer:

The resistor potential increases and the inductor emf decreases.

Explanation:

From Kirchoff's rule, we can easily see that voltage across the inductor decreases steadily in a RL circuit until it finally gets to zero when the circuit is connected to a battery. A graph of the drop in potential across the inductor is attached for more clarity.

The drop shown in figure (b) in the image attached is the drop in potential across the inductor when an RL circuit is connected to a battery.

6 0
4 years ago
Jason has 13720 J of gravitational potential energy standing at the top of a cliff over the lake. If he jumps off the cliff and
Anna [14]

The conservation of energy and Newton's second law allows us to find the results about Jason's falling motion are;

  • The energy when reaching the water is K = 13720 J
  • The average force of the water to stop it is: F = 2744 N

<h3>Energy conservation.</h3><h3> </h3>

The conservation of energy is one of the most important principles of physics, stable that if there is no friction force, mechanical energy is conserved at all points.

Mechanical energy is the sum of kinetic energy plus potential energy.

Let's look for the energy at two points

Starting point. Get higher.

         Em₀ = U = 13720 J

Final point. Lower down.

         Em_f = K

Friction in the air is negligible, so energy is conserved.

          Em_o= Em_f

          K = 13720J

<h3>Kinematics and Newton's law.</h3><h3> </h3>

They indicate that it stops 5m under the water, if we assume that the water acts with a constant force, we can use kinematics and Newton's second law to find this force.

The kinematics expression to find the acceleration is

            v² =v₀² – 2ay

When it stops the speed is zero.

            a = \frac{v_o^2}{2y}  

 

Newton's second law is:

           F = ma

           F = m ( \frac{v_o^2}{2y} )

The expression for the kinetic energy is:

          K = ½ m v₀²

          v_o^2 = \frac{2K}{m}  

Let's substitute.

           F = m (\frac{2K}{m}) \frac{1}{2y}  

           F= \frac{K}{y}  

Let's calculate.

           F= \frac{13720}{5}  

           F = 2744N

In conclusion using conservation of energy and Newton's second law we can find the results about Jason's falling motion are;

  • The energy when reaching the water is K = 13720 J
  • The average force of the water to stop it is: F = 2744 N

Learn more about energy here:  brainly.com/question/14274074

6 0
2 years ago
A loaded 500 kg sled is traveling on smooth horizontal snow at 5 m/s when it suddenly comes to a rough region. The region is 10
sergejj [24]

Answer:

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∆KE = W

½ x m x (v(5)² - v(3)²) = f x d

½ x 500 x (5² - 3²) = f x 10

250 x (25 - 9) = f x 10

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f = 400 N

6 0
3 years ago
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sleet_krkn [62]

Answer:Jack will run faster when he feels like it!

Explanation:

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A 2.0kg rocket is traveling straight up. What force muse be applied to the rocket for it to move at a constant velocity?
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A equal force it always has to be equal
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