Answer:
The answer is;
The mass of the cable is 7.428 kg
Explanation:
Force = 110 N
Mass of block = 20 kg
velocity = 3.9 m/s
We apply the law of motion which is
v² = u² + 2·a·s
Where a = acceleration
s = distance = 1.9 m and
u = initial velocity = 0 m/s
v = velocity = 3.9 m/s
∴ v² = 2·a·s
3.9² = 2×1.9×a which gives
a = 4.003 m/s²
F= m×a
Where F= Force = 110 N
m = mass
a = acceleration = 4.003 m/s²
∴ m = F/a = 110/4.003 = 27.482 kg
Since the mass of the block = 20 kg
Mass of cable + block = 27.482 kg
Mass of cable = 27.428 kg - mass of block = 27.428 kg - 20 kg = 7.428 kg
Mass of cable = 7.428 kg
Answer
given,
mass of block, m = 2 Kg
spring constant, k = 315 N/m
speed of the block, v = 12 m/s
a) Amplitude of the motion
A = 0.956 m
b) maximum acceleration of the block
c) maximum Force
Answer:
a1 = (V2 - V1) / 1 s = 3.75 m/s^2
a2 = (V2 - V1) / (t2 - t1) = (7.5 - 3.75) / 1 s = 3.75 m/s^2
a3 = (V2 - V1) / (t2 - t1) = (7.5 - 3.75) / 1 s = 3.75 m/s^2
A) a = (a1 + a2 + a3) / 3 = 3.75 m/s^2
v = a (t2 - t1)
B) after 1 sec v = 3.75 m / sec^2 * 1 sec = 3.75 m/s
after 2 sec v = v0 + a t = 3.75 m/s + 3.75 m/s^2 * 1 s = 7.5 m/s
C) The velocity increases proportionaly to the time
D) One factor depends on the variation of the acceleration due to gravity because of different positions of measurement (on earth)
A much larger factor is due to air resisance of the air on the falling object
The answer is C. relative dating I think
Answer:
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Explanation:
