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Oksi-84 [34.3K]
3 years ago
12

Nuclear chain reactions within power plants do NOT produce bomb-like explosions primarily because the ________.

Physics
1 answer:
Gelneren [198K]3 years ago
6 0

Answer: D. Density of uranium within nuclear fuel rods is insufficient to become explosive

Explanation: Nuclear power plants use the same fuel as nuclear bombs, i.e. radioactive Uranium-235 isotope. However, in a nuclear power plant, the energy is released more slowly unlike in a nuclear bomb. <em>The energy released is through nuclear fission, and radioactive decay occurs at the same rate as in nuclear bombs. therefore, option A, B</em><em> </em><em>and C are incorrect.</em>

The primary reason why nuclear chain reactions within power plants do NOT produce bomb-like explosions is because the uranium fuel rods used in electricity generation is not sufficiently enriched in Uranium-235 to produce a nuclear detonation. This is the same idea in option D which is the correct option.

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inessss [21]

Answer:

1/ decreases

2/ yes;

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Explanation:

Explanation for 1/ - please see the picture attached below

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3 years ago
suppose a ball had a potential energy of 5 j when you dropped it. What would be its kinetic energy just as it hit the ground. (i
Andru [333]
Since we are ignoring air resistance which is a non-conservative force, the potential energy will be completely converted into kinetic energy, resulting in a final kinetic energy of 5J.
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3 years ago
Integrated Science- 8th grade science
padilas [110]

Answer:

A. a rigorously tested explanation

Explanation:

  • B. and D. are out - theories are not opinionated, they are factual
  • C. is out - not all theories are mathematical
  • A. is the best choice
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2 years ago
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Which of the following is a major ocean on Earth?
yarga [219]
The Indian Ocean. 
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3 0
3 years ago
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Calculate the radius of the orbit of a proton moving at 2.2x10^6 m/s in a magnetic field 0.7 T where v and B are perpendicular.
Juliette [100K]

Answer:

3.28 cm

Explanation:

To solve this problem, you need to know that a magnetic field B perpendicular to the movement of a proton that moves at a velocity v will cause a Force F experimented by the particle that is orthogonal to both the velocity and the magnetic Field. When a particle experiments a Force orthogonal to its velocity, the path it will follow will be circular. The radius of said circle can be calculated using the expression:

r = \frac{mv}{qB}

Where m is the mass of the particle, v is its velocity, q is its charge and B is the magnitude of the magnetic field.

The mass and  charge of a proton are:

m = 1.67 * 10^-27 kg

q = 1.6 * 10^-19 C

So, we get that the radius r will be:

r =  \frac{1.67 * 10^-27 kg * 2.2*10^6 m/s}{1.6 * 10^-19 C* 0.7 T} = 0.0328 m, or 3.28  cm.

8 0
3 years ago
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