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natta225 [31]
3 years ago
15

What is the solution set of the quadratic inequality x²-5≤0

Mathematics
1 answer:
mart [117]3 years ago
5 0

Answer:

X² - 5 = 0

x² = 5

square on both side

x = 5²

x = 25

May mine aswer might be wrong please retrify but as per my point of view it will be write

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I am having trouble understanding this: Sam bought 86 pounds of flour for his bakery. Every day he used the same amount of flour
oksano4ka [1.4K]

Answer:

the average amount of flour used each day=6.08 pounds

Step-by-step explanation:

Sam bought 86 pounds of flour for his bakery.

Every day he used the same amount of flour to make bakery items.

After 10 days, Sam was left with 25.2 pounds of flour.

Now we are asked to find the average pounds of flour that Sam used each day.

Total amount of flour used=86-25.2=60.8 pounds.

As he used the flour equal amount each day for 10 days.

So, the average flour used each day=

amount of flour used/ number of days=60.8/10=6.08.

the average amount of flour used each day=6.08 pounds

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What is Integration ?
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When adding 2/3 + 4/5, what step must be completed first?
Irina18 [472]

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you have to find the smallest common denominator

Step-by-step explanation:

so once the fractions have the same denominator you can add them easily and simplify

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Jalen charges customers a flat fee of $30 to mow their grass plus $8.50 an hour for additional yard work. If Mr. Williams pays J
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She spent 2 and a half hours doing extra work.

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Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?
likoan [24]

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=15,\:\quad a_n=2

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5

=\left(x+3\right)\left(2x^2-11x+5\right)

Factor: 2x^2-11x+5

2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)

=x\left(2x-1\right)-5\left(2x-1\right)

2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)

\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:}

thus zeros of f(x) is

x=-3,\:x=5,\:x=\frac{1}{2}

5 0
3 years ago
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