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timama [110]
3 years ago
11

The side length of a square is equal to? ​

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
5 0

Answer:

the other sides of the square

Step-by-step explanation:

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X^2-x-42<br> what is the fractored forms
igomit [66]
The factored forms of that is (x + 6) (x - 7).

If you have any questions then please leave a comment. Good luck!
5 0
3 years ago
1/8(-8c +16) - 1/3(6+3c)
Bess [88]

Answer:

-2c

Step-by-step explanation:

5 0
3 years ago
Can someone explain division of polynomials to me please.
kykrilka [37]

Answer: Division of Polynomials is just like the long division  that most of us despise but this division is with Variables

Step-by-step explanation:

Example

With whatever equation you have you will

  • First: set up the division putting the dividend inside the divisor outside and to the left
  • Second: Ignore everything past the leading terms and just focus on the leading _ of the divisor and the leading _ of the dividend (just like in regular long division.
  • Thirdly: Take whatever is on top and multiply is by the divisor {What is on the side} carry the result underneath put it exactly below the number from the dividend
  • Fourth: Multiply the number that is on top by the number that is on the side, carry what is on the side underneath putting it below the other dividend.
  • Fifth: Do the subtraction
  • Sixth To subtract change all the signs in the second line, then add down.
  • Next: Carry down that last term from the dividend
  • From there you multiply and then add down again and you should be left with the answer....

If this was to many words let me know and I will upload a picture and explain with a real equation.

3 0
3 years ago
The length of a rectangle is four times its width.
Irina-Kira [14]

Answer:

Length = 24 yd

Width = 6 yd

Step-by-step explanation:

To start out, we can begin by saying that "l" is the length of the rectangle, and "w" is the width.

Since we know that the length (l) is 4 times its width we can say that 4 times the width is equal to its length. We would write this out this way :

4w = l

Next, we know that the perimeter is 60yd (as it is given in the question). We also know that the perimeter of a rectangle is all of its sides, added. Meaning the length plus the length, plus the width and the width. So, we can use the equation :

2l + 2w = p

"p" being the perimeter. And, since the perimeter is 60, we can place in 60 for "p"

2l + 2w = 60

Now we can use this information to combine the terms, and find the width and length. We first do this by noticing that in the first equation, it shows that "l" (the length) is equal to 4w. This means that we can put 4w in place of the "l" in the second equation. We can do this, becuase we know that "l" is equal to 4w. (from the first eqaution)

2 (4w) + 2w = 60

Now, we solve

2 * 4w = 8w

8w + 2w = 10w

So now we have :

10w = 60

To get the width, all we have to do is simply get "w" alone. We can do this by dividing both sides by 10.

10w = 60

/10     /10

w = 6

Therefore, the width is 6.

Now, going back to the first equaiton, we already know that the length is 4 times the width, meaning all we have to do is multiply 6 by 4 to get the length.

6 * 4 = 24.

Therefore, the length is 24.

Lastly, to check and make sure we are correct, we can go back to the second equation. 2l + 2w = 60

2 (24) + 2 (6) = 60

2 * 24 = 48

2 * 6 = 12

48 + 12 = 60

60 = 60

Now, we officially know that the length of the rectangle is 24 and the width is 6.

6 0
2 years ago
How can you write the expression with rationalized denominator? 2+sqrt3(3)/sqrt3(6)
joja [24]
So we have a 6 at the bottom, and the root is 3, so hmm how to take it out, simple enough, just let's get something to make the 6 a 6³, so it comes out of the root

so 

\bf \cfrac{2+\sqrt[3]{3}}{\sqrt[3]{6}}\cdot \cfrac{\sqrt[3]{6^2}}{\sqrt[3]{6^2}}\implies \cfrac{(2+\sqrt[3]{3})(\sqrt[3]{6^2})}{(\sqrt[3]{6})(\sqrt[3]{6^2})}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{3}\cdot \sqrt[3]{36}}{\sqrt[3]{6^3}}&#10;\\\\\\&#10;\cfrac{2\sqrt[3]{36}+\sqrt[3]{3\cdot 36}}{6}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{108}}{6}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{3^3\cdot 4}}{6}&#10;\\\\\\&#10;\cfrac{2\sqrt[3]{36}+3\sqrt[3]{ 4}}{6}
8 0
3 years ago
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