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1 year ago

Can someone help me with this question ?

Mathematics

1 answer:

Juli2301 [7.4K]1 year ago

4 0

Answer:

it is median

Step-by-step explanation:

because it have number in alphabetic order

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Which quadratic equation has the roots -1+4i and -1-4i

AysviL [449]

Answer:

Step-by-step explanation:

Solve the quadratic in answer choice C using the quadratic formula:

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}$ .

Here a=1, b=2, and c=17.

Substitute and you'll have:

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{-2+/-\sqrt{(-2)^2-4(1)(17)} }{2(1)}=\frac{-2+/-\sqrt{4-68}}{2)}$

$\frac{-2+/-\sqrt{-64} }{2}=\frac{-2+/-8i }{2}=-1+/- 4i$

6 0

3 years ago

Let f(x) = 1/x^2 (a) Use the definition of the derivatve to find f'(x). (b) Find the equation of the tangent line at x=2

Verdich [7]

Answer:

(a) $f'(x)=-\frac{2}{x^3}$

(b) $y=-0.25x+0.75$

Step-by-step explanation:

The given function is

$f(x)=\frac{1}{x^2}$ .... (1)

According to the first principle of the derivative,

$f'(x)=lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{1}{(x+h)^2}-\frac{1}{x^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{x^2-(x+h)^2}{x^2(x+h)^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{x^2-x^2-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-h(2x+h)}{hx^2(x+h)^2}$

Cancel out common factors.

$f'(x)=lim_{h\rightarrow 0}\frac{-(2x+h)}{x^2(x+h)^2}$

By applying limit, we get

$f'(x)=\frac{-(2x+0)}{x^2(x+0)^2}$

$f'(x)=\frac{-2x)}{x^4}$

$f'(x)=\frac{-2)}{x^3}$ .... (2)

Therefore $f'(x)=-\frac{2}{x^3}$ .

(b)

Put x=2, to find the y-coordinate of point of tangency.

$f(x)=\frac{1}{2^2}=\frac{1}{4}=0.25$

The coordinates of point of tangency are (2,0.25).

The slope of tangent at x=2 is

$m=(\frac{dy}{dx})_{x=2}=f'(x)_{x=2}$

Substitute x=2 in equation 2.

$f'(2)=\frac{-2}{(2)^3}=\frac{-2}{8}=\frac{-1}{4}=-0.25$

The slope of the tangent line at x=2 is -0.25.

The slope of tangent is -0.25 and the tangent passes through the point (2,0.25).

Using point slope form the equation of tangent is

$y-y_1=m(x-x_1)$

$y-0.25=-0.25(x-2)$

$y-0.25=-0.25x+0.5$

$y=-0.25x+0.5+0.25$

$y=-0.25x+0.75$

Therefore the equation of the tangent line at x=2 is y=-0.25x+0.75.

5 0

3 years ago

Simplify the expression 6ab + 3ab - 7ab. What is the coefficient of the simplified expression?

Vika [28.1K]

The simplified equation is 2ab, so the coefficient would be 2.

5 0

2 years ago

HELPP!! BRAINLIEST??

ICE Princess25 [194]

Answer:

answer number 4 I believe

6 0

2 years ago

Read 2 more answers

What is the measure of the missing angle?<br> PICTURE BELOW \/

jeka57 [31]

Answer:

The measure of the missing angle is 90°

Step-by-step explanation:

∵ This figure is a quadrilateral

∴ the sum of measures of its angles = 360°

∴ m∠x = 360 - 107 - 72 - 91 = 90°

6 0

3 years ago