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3 years ago

Round 46.82 to the nearest ten

Mathematics

1 answer:

lord [1]3 years ago

7 0

50, 6 makes the 4 go up, and you just leave the decimal numbers be

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Jayden and Sheridan both tried to find the missing side of the right triangle. A right triangle is shown. One leg is labeled as

stellarik [79]

Answer:

Sheridan's Work is correct

Step-by-step explanation:

we know that

The lengths side of a right triangle must satisfy the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$

where

a and b are the legs

c is the hypotenuse (the greater side)

In this problem

Let

$a=7\ cm\\c=13\ cm$

substitute

$13^{2}=7^{2}+b^{2}$

Solve for b

$169=49+b^{2}$

$b^{2}=169-49$

$b^{2}=120$

$b=\sqrt{120}\ cm$

$b=10.95\ cm$

we have that

Jayden's Work

$a^{2}+b^{2}=c^{2}$

$a=7\ cm\\b=13\ cm$

substitute and solve for c

$7^{2}+13^{2}=c^{2}$

$49+169=c^{2}$

$218=c^{2}$

$c=\sqrt{218}\ cm$

$c=14.76\ cm$

Jayden's Work is incorrect, because the missing side is not the hypotenuse of the right triangle

Sheridan's Work

$a^{2}+b^{2}=c^{2}$

$a=7\ cm\\c=13\ cm$

substitute

$7^{2}+b^{2}=13^{2}$

Solve for b

$49+b^{2}=169$

$b^{2}=169-49$

$b^{2}=120$

$b=\sqrt{120}\ cm$

$b=10.95\ cm$

therefore

Sheridan's Work is correct

6 0

3 years ago

Read 2 more answers

What’s the perfect square of 4x^2

kirza4 [7]

16x^2 is the perfect square of 4x^2

8 0

3 years ago

Read 2 more answers

The longest side of an acute triangle measures 30 inches. The two remaining sides are congruent, but their length is unknown.

lakkis [162]

The smallest perimeter is 72.44 inches. The longest side of an acute triangle measures 30 inches. The two remaining sides are congruent, but their length is unknown. As much as possible, the sum of the length of the two remaining side must be greater than the other side. Given the side is 30, then the sum of the two remaining sides should be greater than 30 inches.

7 0

3 years ago

Write the equation of the line in fully simplified slope-intercept form.

PtichkaEL [24]

Answer:

Consider points (0, -5) and (-6, -1)

» General equation of a line:

${ \tt{y = mx + c}}$

m is slope
c is y-intercept

 Slope (m):

${ \tt{m = \frac{ - 1 - ( - 5)}{ - 6 - 0} }} \\ \\ { \tt{m = \frac{4}{ - 6} }} \\ \\ { \tt{m = - \frac{2}{3} }}$

 y-intercept (c):

${ \tt{y = mx + c}}$

consider point (0, -5)

${ \tt{ - 5 = c}} \\ { \tt{c = - 5}}$

Equation:

${ \boxed{ \tt{y = - \frac{2}{3} x - 5}}}$

8 0

2 years ago

An artist used a scale factor of 1 in=8 ft to create a model of a building. if the actual building has a height of 64 feet, how

nalin [4]

Answer:

Okay, so what I think you mean to ask what the scale factor between the model and actual building is, so i crunched the numbers. if 1 in equaled 8 feet and the actual thing was 64 ft, then we can just say that 64 divided by 12 is 5.3, so the model could be

5.3 ft. is the size of the model

BUT

you said how many feet are they apart so in inches its 705, in ft its 58.75

Step-by-step explanation:

a foot is 12 in.

64/12 is 5.3

64 ft is 768 inches, and 5.3 is 63.

768-63 = 705.

there are 705 inches in difference, in feet its 58.75

8 0

3 years ago