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Mandarinka [93]
3 years ago
15

(6,3) -> (-3/2x , 2/3y) -> (x + 6 , y - 4) -> (2/3x , -3/2y)

Mathematics
1 answer:
Oliga [24]3 years ago
4 0

Answer:

Please refer to the attached image.

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Plz guys help i need asap<br> its part b im stuck
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Answer:

a.2nd quarter with 9 goals

b. 4.8 goals

c. 4 goals

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a. The mode is defined as the most appearing data point or the data point with the highest frequency..

From our data(for away goals):

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  • 2nd quarter-9
  • 3rd quarter-7
  • 4th quarter-4

Hence, the 2nd quarter has the mode for away goals with 9 goals.

b. Mean is defined as the average of a set of data points.

#We calculate the totals goals per quarter, sum over all quarters then divide by the number of games, 10:

\bar x=\frac{1}{n}\sum{x_i}\\1^{st }_g=Away+Home=5+2=7\\\\2^{nd}_g=Away+Home=4+9=13\\\\3^{rd}_g=Away+Home=8+7=15\\\\4^{th}_g=Away+Home=9+4=13\\\\\bar x=\frac{1}{n}\sum{x_i}=\frac{1}{10}(7+13+15+13)=4.8

Hence, the mean number of goals per quarter is 4.8 goals

c. To find the number of more home goals than away goals, we subtract from their summations as:

g_m=\sum{g_h}-\sum{g_a}\\\\=(5+4+8+9)-(2+9+7+4)\\\\=26-22\\\\=4

Hence, there are 4 more home goals than away goals.

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