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dmitriy555 [2]
3 years ago
15

Monobromination of toluene gives a mixture of three bromotoluene products. Draw and name them.

Chemistry
1 answer:
Art [367]3 years ago
5 0

Answer:

<em>o</em>-bromotoluene, <em>m</em>-bromotoluene  and <em>p</em>-bromotoluene.

Explanation:

Hello,

In this case, on the attached picture you will find the reaction which yields <em>o</em>-bromotoluene as the first product, <em>m</em>-bromotoluene as the second product and <em>p</em>-bromotoluene as the last one since the substitution could be done at the second (ortho), third (meta) or fourth (para) carbons on the toluene.

Regards.

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Compare the wavelength and frequency of a radio wave to the wavelength and frequency of a gamma ray?
IgorC [24]

Answer:

Wavelength of Radio wave = 10² meter = 100 meters, frequency 10 power 6 htz,

Wavelength of gamma ray = 10 power -12 meters = 0.000000000002 meters, frequency 10 power 20 htz

frequenc

Explanation:

6 0
3 years ago
Hydrogen cyanide, HCN, can be made by a two-step process. First, ammonia reacts with O2 to give nitric oxide, NO.
stealth61 [152]

Answer:

The mass of HCN is 79.65 g.

The mass of reactant which remain at the end of both reactions is 88.5 g.

Explanation:

Given that,

Mass of ammonia = 50.2 g

Mass of methane = 48.4 g

Hydrogen cyanide, HCN, can be made by a two-step process

Ammonia reacts with O₂ to give nitric oxide NO.

The reaction is,

4NH_{3}+5O_{2}\Rightarrow 4NO+6H_{2}O

We need to calculate the mole of NO

Using given data,

2.25 g NH_{3}=\dfrac{50.2}{17}= 2.95\ mole\ NH_{3} [/tex]

4\ mole NH_{3}\ glose 4\ mol NO

2.95 mol NH₃ will produced 2.95 mol NO

Then nitric oxide reacts with methane,

The reaction is,

2NO+2CH_{4}\Rightarrow 2HCN+2H_{2}O+H_{2}

We need to calculate the mole of methane

Using given data,

mole\ of\ methane=\dfrac{48.4}{16}

mole\ of\ methane = 3.03\ moles

2 mole NO produced 2 mole HCN

2.95 mol NO will produced \dfrac{2.95\times3.03}{3.03}= 2.95 mol HCN

We need to calculate the mass of HCN

Using formula of mass

m=N\times M

Where, N = number of mole

M = molecular mass

Put the value into the formula

m=2.95\times27

m= 79.65\ g

The mass of HCN is 79.65 g.

We need to calculate the mass of NO

Using formula of mass

m=N\times M

Where, N = number of mole

M = molecular mass

Put the value into the formula

m=2.95\times30

m= 88.5\ g

Hence, The mass of HCN is 79.65 g.

The mass of reactant which remain at the end of both reactions is 88.5 g.

4 0
3 years ago
3. If you start with 8x1025 molecules of Cl, and 25 grams of KI, how many grams of KCl would
miskamm [114]

Answer:

Percent yield = 89.1%

Explanation:

Based on the equation:

Cl₂ + 2KI → 2KCl + I₂

<em>1 mole of Cl₂ reacts with 2 moles of KI to produce to moles of KCl</em>

<em />

To solve this quesiton we must find the moles of each reactant in order to find the limiting reactant. With the limiting reactant we can find the moles of KCl and the mass:

<em>Moles Cl₂:</em>

8x10²⁵ molecules * (1mol / 6.022x10²³ molecules) = 133 moles

<em>Moles KI -Molar mass: 166.0028g/mol-</em>

25g * (1mol / 166.0028g) = 0.15 moles

Here, clarely, the KI is the limiting reactant

As 2 moles of KI produce 2 moles of KCl, the moles of KCl produced are 0.15 moles. The theoretical mass is:

0.15 moles * (74.5513g / mol) =

11.2g KCl

Percent yield is: Actual yield (10.0g) / Theoretical yield (11.2g) * 100

<h3>Percent yield = 89.1%</h3>
3 0
3 years ago
Write the balanced NET IONIC equation for the reaction that occurs when perchloric acid and calcium hypochlorite are combined. I
Elanso [62]

Answer:

H^+(aq)+(ClO)^-(aq)\rightarrow HClO{(aq)}

Explanation:

Hello there!

In this case, since perchloric acid is HClO4 and is a strong acid and calcium hypochlorite is Ca(ClO)2, the undergoing molecular chemical reaction turns out:

2HClO_4{(aq)}+Ca(ClO)_2{(aq)}\rightarrow 2HClO{(aq)}+Ca(ClO_4)_2{(aq)}

Thus, since the resulting hypochlorous acid is weak, it does not fully ionize, so it remains unionized, however, we can write the ions for the other species:

2H^++2(ClO_4)^-+Ca^{2+}+2(ClO)^-\rightarrow 2HClO{(aq)}+Ca^{2+}+2(ClO_4)^-

Now, we can cancel out the spectator ions, calcium and perchlorate, to obtain:

2H^+(aq)+2(ClO)^-(aq)\rightarrow 2HClO{(aq)}\\\\H^+(aq)+(ClO)^-(aq)\rightarrow HClO{(aq)}

Best regards!

3 0
3 years ago
Please help me!!!!!!!!!!!!!
Verizon [17]

double-displacement reaction

Explanation:

We have the chemical reaction:

Na₂S (aq) + Cd(NO₃)₂ (aq) → CdS (s) + 2 NaNO₃ (aq)

where:

(aq) - aqueous

(s) - solid

This is a double-displacement reaction because the reactants exchange atoms or group of atoms between themselves to form the products. To drive the reaction to the right, one of the products is a precipitate.

Generally we can express the double-displacement reaction as following:

AB + CD → AC + BD

Learn more about:

types of chemical reactions

brainly.com/question/13824617

#learnwithBrainly

3 0
2 years ago
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