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dmitriy555 [2]
3 years ago
15

Monobromination of toluene gives a mixture of three bromotoluene products. Draw and name them.

Chemistry
1 answer:
Art [367]3 years ago
5 0

Answer:

<em>o</em>-bromotoluene, <em>m</em>-bromotoluene  and <em>p</em>-bromotoluene.

Explanation:

Hello,

In this case, on the attached picture you will find the reaction which yields <em>o</em>-bromotoluene as the first product, <em>m</em>-bromotoluene as the second product and <em>p</em>-bromotoluene as the last one since the substitution could be done at the second (ortho), third (meta) or fourth (para) carbons on the toluene.

Regards.

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Calculate the equilibrium constant for the reaction: 2 Cr + 3 Pb2+ ----&gt; 3 Pb + 2 Cr3+ at 25oC. Eocell = 0.61 V
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Answer:

The value is  K  =  8*10^{61}

Explanation:

From the question we are told that

    The equation is  2 Cr  +  3Pb^{2+} \to 3Pb + 2Cr^{3+}

     The  temperature is  T = 25^oC =  298 K   [room  \ temperature ]

     The  emf at standard condition is  E^o_{cell}  =  0.61 \  V

Generally at the cathode

      3Pb^{2+}(aq) + 6 e- --> 3Pb(s)

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      2Cr^{3+} + 6e^- \to  2Cr

Generally for an  electrochemical reaction, at room temperature the Gibbs free energy is mathematically represented as  

       G =  n*  F *  E^o_{cell}

Here  n  is  the no of electron  with value n = 6

       F  is  the Faraday's constant with value 96487 J/V

  =>   G =  6  * 96487 *  0.61

  =>   G = 3.5 *10^{5} \  J

This Gibbs free energy can also be represented mathematically as

       G =  RTlogK

Here  R  is the cell constant with value 8.314J/K

           K is the equilibrium constant

From above

=>  K  =  antilog^{\frac{G}{ RT} }

Generally  antilog =  2.718

=>K  =  2.718^{\frac{3.5 *10^5}{ 8.314* 298} }

=>   K  =  8*10^{61}

       

         

       

         

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