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3 years ago

What is the product of 2.7 and 1.5

Mathematics

2 answers:

notsponge [240]3 years ago

8 0

Answer:

4.05

Step-by-step explanation:

.....................

SOVA2 [1]3 years ago

5 0

Answer:

4.05

Step-by-step explanation:

2.7*1.5=4.05. Hope this helps.

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Find all values of x (if any) where the tangent line to the graph of the function is horizontal

ratelena [41]

the horizontal tangent line mean y'=0

8 - 2x = 0

x = 4

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3 years ago

Jacob sells lemonade at a park. His cost to sell the lemonade is a one-time fee for the table,

Nana76 [90]

Answer:y=12 x=00

Step-by-step explanation:

you can not

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2 years ago

Find the midpoint of A and B where A has coordinates (2,3) and B has coordinates (8,9).

Effectus [21]

Answer:

(5,6)

Step-by-step explanation:

Add both "x" coordinates, divide by 2.

Add both "y" coordinates, divide by 2.

(2,3)

(8,9)

10 divided by 2=5

12 divided by 2 is 6

please mark me the brainiest i hope this has helped

7 0

3 years ago

if you drove into the ocean and went under the water 6 feet wiuld youbsay you were -6ft under the water or 6ft under yhe water

-Dominant- [34]

Answer:

Both are fine i think

Step-by-step explanation:

6 0

2 years ago

An NFL coach sometimes uses a defense that utilizes 3 defensive linemen, 4 linebackers, and 4 defensive backs. His roster (the p

Alexandra [31]

Answer:

68,600

Step-by-step explanation:

The order of the players is not important. For example, a defensive line of Shaq Lawson, Ed Oliver and Jerry Hughes is the same as a defensive line of Ed Oliver, Shaq Lawson and Jerry Hughes. So we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Defensive Lineman:

3 from a set of 8. So

$C_{8,3} = \frac{8!}{3!5!} = 56$

56 combinations of defensive lineman

Linebackers:

4 from a set of 7. So

$C_{7,4} = \frac{7!}{4!3!} = 35$

35 combinations of linebackers

Defensive backs:

4 from a set of 7. So

$C_{7,4} = \frac{7!}{4!3!} = 35$

35 combinations of defensive backs

How many different ways can the coach pick the 11 players to implement this particular defense?

56*35*35 = 68,600

68,600 different ways can the coach pick the 11 players to implement this particular defense

7 0

3 years ago