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den301095 [7]
2 years ago
5

The following equation shows the position of a particle in time t, x=at2i + btj where t is in second and x is in meter. A=2m/s2,

b=1m/s. Find
A, the average velocity of the particle in the time interval t1=2sec and t2=3sec
B, the velocity and acceleration at any time t.
C, the average acceleration in the time interval given in part (a)
Physics
1 answer:
sattari [20]2 years ago
5 0

(a) The average velocity of the particle in the time interval t₁=2sec and t₂=3sec is 10 m/s.

(b) The velocity and acceleration at any time t is v =  (2ati + bj) m/s and a = 2ai m/s²

(c)  The average acceleration in the time interval given in part (a)​ is 4 m/s².

<h3>Position of the particle</h3>

x = at²i + btj

x = 2t²i + tj

<h3>Average velocity, at t₁=2sec and t₂=3sec</h3>

Δv = Δx/Δt

x(2) = 2(2)²i + 2j

x(2) = 8i + 2j

|x(2)| = √(8² + 2²) = 8.246

x(3) =  2(3)²i + 3j

x(3) = 18i + 3j

|x(3)| = √(18² + 3²) = 18.248

Δv = (18.248 - 8.246)/(3 - 2)

Δv =  10 m/s

<h3>Velocity and acceleration at any time, t</h3>

x = at²i + btj

v = dx/dt

v =  (2ati + bj) m/s

a = dv/dt

a = 2ai m/s²

<h3>Average acceleration</h3>

a = 2ai m/s²

a = 2(2)(1)

a = 4 m/s²

Learn more about average acceleration here: brainly.com/question/104491

#SPJ1

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