Answer:
(a) Final speed of block = 3.2896 m/s
(b) 6.7350 m/s is the speed of the bullet-block center of mass?
Explanation:
Given that:
Mass of bullet (m₁) = 6.20 g
Initial Speed of bullet (u₁) = 929 m/s
Final speed of bullet (v₁) = 478 m/s
Mass of wooden block (m₂) = 850g
Initial speed of block initial (u₂) = 0 m/s
Final speed of block (v₂) = ?
<u>By the law of conservation of momentum as:</u>
<u>m₁×u₁ + m₂×u₂ = m₁×v₁ + m₂×v₂</u>
6.20×929 + 850×0 = 6.20×478 + 850×v₂
Solving for v₂, we get:
<u>v₂ = 3.2896 m/s</u>
Let the V be the speed of the bullet-block center of mass. So,
V = [m₁* u₁]/[m₁ + m₂] (p before collision = p after collision)
= [6.2 *929]/[5.2+850]
<u>V = 6.7350 m/s
</u>
It's kinetic energy as the ball the ball isn't raised above the ground it does not have any gravitational potential energy.
To find the kinetic energy of the ball you will have to use the formula:
KE=0.5 x m x v squared
m being mass and v being velocity
so the calculation is:
0.5 x 2 x 10 x 10= 100J
Answer:
Velocity v= 12.25 
Explanation:
The first rock dropped give the distance Y in meters
Now the motion of the second rock the time change so to know the velocity
The second one (4.1 kg ball)
This is because the mxv is greater than the other one.
For the 4.1kg ball, the force it’s moving on is 4.92N
As for the 3.2kg ball, it’s moving with a force of 0.9N. Much less than the other one.
The first thing we have to do for this case is write the kinematic equationsto
vf = a * t + vo
rf = a * (t ^ 2/2) + vo * t + ro
Then, for the bolt we have:
100% of your fall:
97 = g * (t ^ 2/2)
clearing t
t = root (2 * ((97) / (9.8)))
t = 4.449260429
89% of your fall:
0.89*97 = g * (t ^ 2/2)
clearing t
t = root (2 * ((0.89 * 97) / (9.8)))
t = 4.197423894
11% of your fall
t = 4.449260429-4.197423894
t = 0.252
To know the speed when the last 11% of your fall begins, you must first know how long it took you to get there:
86.33 = g * (t ^ 2/2)
Determining t:
t = root (2 * ((86.33) / (9.8))) = <span>
4.19742389 </span>s
Then, your speed will be:
vf = (9.8) * (4.19742389) = 41.135 m / s
Speed just before reaching the ground:
The time will be:
t = 0.252 + <span>
4.197423894</span> = <span>
4.449423894</span> s
The speed is
vf = (9.8) * (4.449423894) =<span>
<span>43.603</span></span> m / s
answer
(a) t = 0.252 s
(b) 41,135 m / s
(c) 43.603 m / s
