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Dahasolnce [82]
3 years ago
14

A tennis racket hits a tennis ball with a force of F=at−bt2, where a = 1290 N/ms , b = 330 N/ms2 , and t is the time (in millise

conds). The ball is in contact with the racket for 2.80 ms . If the tennis ball has a mass of 55.6 g , what is the resulting velocity of the ball, v, after the ball is hit by the racket?
Physics
1 answer:
denpristay [2]3 years ago
6 0

Answer:

The resulting velocity of the ball after it hits the racket was of V= 51.6 m/s

Explanation:

m= 55.6 g = 0.0556 kg

t= 2.8 ms = 2.8 * 10⁻³ s

F= 1290 N/ms * t - 330 N/ms² * t²

F= 1024.8 N

F*t= m * V

V= F*t/m

V= 51.6 m/s

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Answer:

A) 50 seconds

B) 200 m

Explanation:

They are 500 metres apart.

And one of the bike loves at 6 m/s while the other loves at 4 m/s.

A) Let distance of the 6 m/s bike before they meet be x.

Thus, time = x/6

Since time = distance/speed

For the second bike at 4 m/s, his distance covered before they meet will be 500 - x

Thus, time = (500 - x)/4

Now they will meet each other at the same time. Thus;

x/6 = (500 - x)/4

Cross multiply to get;

4x = 3000 - 6x

6x + 4x = 3000

10x = 3000

x = 3000/10

x = 300 m

Thus, time will be;

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B) Distance covered by the slower bike is (500 - x)

Since from a above, x = 300

Thus; distance = 500 - 300 = 200 m

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3 years ago
An observation which is descriptive is considered
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6 0
4 years ago
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Determine the average acceleration for x(t)=19t^2+7t^3 for a time interval between 3 and 9 seconds
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Answer:

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a = (2043 − 303) / (9 − 3)

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Use appropriate units.

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