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Minchanka [31]
3 years ago
11

A hot brass plate is having its upper surface cooled by impinging jet of air at temperature of 15°c and convection heat transfer

coefficient of 220 w/m2•k. the 10-cm thick brass plate (ρ = 8530 kg/m3, cp = 380 j/kg•k, k = 110 w/m•k, and α = 33.9×10–6 m2/s) has a uniform initial temperature of 700°c, and the bottom surface of the plate is insulated. determine the temperature at the center plane of the brass plate after 3 minutes of cooling. solve this problem using analytical one term approximation method (not the heisler charts).
Physics
1 answer:
Elodia [21]3 years ago
4 0
200 degrees because I need the points
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Please help me with my physics I do not understand! Please provide work thank you.
Studentka2010 [4]
Fe=K Q1/Q2/d2
Q1 is the first charge
Q2 is the second charge
d is the distance
K= 9x10^9 NM^2/C2
Now let’s plug the numbers
Fe=9x10^9NM^2/C2 (2x10^-4C)(8x10^-4C) / (0.3m^2) you notice we took away the negative charges when we plugged the charges
Ok now we notice that we have C2 which is C to the power 2 we can write it as C^2 and we have two CSU’s beside each one of the charges we can get rid of them all by curtailment
And we can curtailment the M^2and the other M^2
Now we left with only 9x10^9N (2x10^-4)(8x10^-4)/ 0.3
Let’s multiply the (9)(2)(8)=144
And add the exponents (9)+(-4)+(-4)=1
So now we got 144x10N divide by the distance which is 0.3
144x10N / 0.3 = 4800N
Hope it helps u understand :)
3 0
3 years ago
A cathode-ray tube (CRT) is an evacuated glass tube. Electrons are produced at one end, usually by the heating of a metal. After
Kobotan [32]

Answer: v = 5.79 * 10^10m/s.

Explanation: By using the work-energy theorem, we know that the work done on the electron by the potential difference equals the kinetic energy of the electrons.

Mathematically, we have that

qV = 1/2mv²

q= magnitude of an electronic charge = 1.609*10^-16c

V= potential difference = 95v

m = mass of an electronic charge = 9.11* 10^-31kg.

v = velocity of electron.

Let us substitute the parameters, we have that

1.609*10^-16 * 95 = (9.11*10^-31 * v²) /2

1.609*10^-16 * 95 * 2 = 9.11*10^-31 * v²

305.71 * 10^-16 = 9.11 * 10^-31 * v²

v² = 305.71 * 10^-16/ 9.11 * 10^-31

v² = 3.355 * 10^21.

v = √3.355 * 10^21

v = 5.79 * 10^10 m/s

5 0
3 years ago
A car moving at 10 m/s crashes into a tree and stops in 0.26 s. calculate the force the seat belt exerts on a passenger in the c
Sedaia [141]
A=(Vo-V)/t=(10-0)/0.26=10/0.26=38.46m/s2
F=ma=70*38.46=2692.3N
4 0
3 years ago
Read 2 more answers
What is the magnitude e of the electric field at point p? throughout this part, express your answers in terms of the constant k,
amm1812
The strength of the electric field is generally equal to 

E = F/Q

However, this could be modified in terms of charge and distance,d.
E = kQ/d²
The k is actually a constant which is equal to 1/4π∈₀

Since no given quantitative data, the answer should just be E = kQ/r².
5 0
3 years ago
If you triple the speed from 20km/h to 60km/h, by what factor does the KE increase?
sertanlavr [38]

Answer:

<em>The kinetic energy increases by a factor of 9 </em>

Explanation:

<u>Kinetic Energy </u>

It's the energy related to the speed of an object and is calculated by the formula

\displaystyle K=\frac{mv^2}{2}

Let's suppose the initial speed of the mass is v_o, then the kinetic energy is

\displaystyle K_o=\frac{mv_o^2}{2}

Now the speed will triple, i.e. v_1=3v_o. The new kinetic energy is

\displaystyle K_1=\frac{mv_1^2}{2}

\displaystyle K_1=\frac{m(3v_o)^2}{2}

\displaystyle K_1=9\frac{mv_o^2}{2}

Thus

K_1=9K_o

The kinetic energy increases by a factor of 9

Let's check with numbers: v_o=20,\ v_1=60

\displaystyle K_o=\frac{m20^2}{2}=200m

\displaystyle K_1=\frac{m60^2}{2}=1800m

The relation is

\displaystyle \frac{K_1}{K_o}=9

The new kinetic energy is nine times the initial kinetic energy.

5 0
3 years ago
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