- Mass of the car (m) = 2000 Kg
- Initial velocity (u) = 15 m/s
- Force (F) = 10000 N
- Time (t) = 3 s
- Let the acceleration be a.
- By using the formula, F = ma, we get,
- 10000 N = 2000 Kg × a
- or, a = 10000 N ÷ 2000 Kg
- or, a = 5 m/s^2
- Let the final velocity be v.
- By using the formula, v = u + at, we get,
- v = 15 m/s + 5 m/s^2 × 3 s
- or, v = 15 m/s + 15 m/s
- or, v = 30 m/s
<u>Answer</u><u>:</u>
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Hope you could get an idea from here.
Doubt clarification - use comment section.
Answer:
68.8 Hz
137.6 Hz, 206.4 Hz
Explanation:
L = Length of tube = 2.5 m
v = Velocity of sound in air = 344 m/s
Distance between nodes is given by
Where n = 0, 1, 2, 3, ...
Making n+1 = n
where n = 1, 2, 3 .....
For fundamental frequency n = 1
Frequency is given by
The fundamental frequency is 68.8 Hz
First overtone
Second overtone
The overtones are 137.6 Hz, 206.4 Hz