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Minchanka [31]
3 years ago
11

A hot brass plate is having its upper surface cooled by impinging jet of air at temperature of 15°c and convection heat transfer

coefficient of 220 w/m2•k. the 10-cm thick brass plate (ρ = 8530 kg/m3, cp = 380 j/kg•k, k = 110 w/m•k, and α = 33.9×10–6 m2/s) has a uniform initial temperature of 700°c, and the bottom surface of the plate is insulated. determine the temperature at the center plane of the brass plate after 3 minutes of cooling. solve this problem using analytical one term approximation method (not the heisler charts).
Physics
1 answer:
Elodia [21]3 years ago
4 0
200 degrees because I need the points
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What is the difference between a physical and a chemical equilibrium?
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I found this for you

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A uniform electric field of magnitude 375 n/c pointing in the positive x - direction acts on an electron, which is initially at
Finger [1]
(a) The force exerted by the electric field on the electron is given by the product between the electron charge q and the intensity of the electric field E:
F=qE=(1.6 \cdot 10^{-19}C)(375 N/C)=6\cdot 10^{-17}N
Under the action of this force, the electron moves by:
\Delta x = 3.20 cm=0.032 m
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W=F \Delta x= (6\cdot 10^{-17}N)(0.032 m)=1.9 \cdot 10^{-18}J

(b) The electron is initially at rest and it starts to move under the action of the electric field. This means that as it moves, it acquires kinetic energy and it loses potential energy. The change in potential energy is the opposite of the work done by the electric field:
\Delta U = U_f - U_i = -1.9 \cdot 10^{-18} J
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(c) For the conservation of energy, the sum of the kinetic energy and potential energy of the electron at the beginning of the motion and at the end must be equal:
U_i + K_i = U_f + K_f (1)
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v_f= \sqrt{ -\frac{2 \Delta U}{m_e} }= \sqrt{- \frac{2(-1.9 \cdot 10^{-18} J)}{9.1 \cdot 10^{-31} kg} } =2.04 \cdot 10^6 m/s



7 0
3 years ago
The kinetic energy of an object with a mass of 6.8 kg and a velocity of 5.0 m/s is [BLANK] J. (Report the answer to two signific
dmitriy555 [2]
<h2>Hello!</h2>

The answer is:

The kinetic energy of the object is equal to 85 J.

<h2>Why?</h2>

The kinetic energy involves the speed and the mass of an object in motion. We can calculate the following the work needed to speed an object (kinetic energy) using the equation:

KineticEnergy=\frac{1}{2}mv^{2}

Where,

m, is the mas of the object

v, is the speed of the object.

Now, we are given:

mass=m=6.8kg\\speed=v=5\frac{m}{s}

So, substituting and calculating the kinetic energy of the object, we have:

KineticEnergy=\frac{1}{2}*6.8kg*(5\frac{m}{s})^{2}

KineticEnergy=\frac{1}{2}*6.8kg*(25\frac{m^{2}}{s^{2}})

KineticEnergy=\frac{1}{2}*170kg\frac{m^{2}}{s^{2}}

KineticEnergy=85kg\frac{m^{2}}{s^{2}}=85J

We have that the kinetic energy of the object is equal to 85 J.

Have a nice day!

8 0
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7 0
3 years ago
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