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motikmotik
3 years ago
11

A 10-foot ladder is leaning straight up against a wall when a person begins pulling the base of the ladder away from the wall at

the rate of 1 foot per second. Calculate the true distance between the top of the ladder and the ground when the base of the ladder is 9 feet from the wall.
Physics
1 answer:
docker41 [41]3 years ago
8 0

Answer:

y = 4.36

Explanation:

Let the height of the ladder be L

L = 10

Also:

  • Let x = distance\ from\ the\ base\ of\ the\ ladder
  • Let y = height\ of\ the\ base\ of\ the\ ladder

When the ladder leans against the wall, it forms a triangle and the length of the ladder forms the hypotenuse.

So, we have:

L^2 = x^2 + y^2 --- Pythagoras Theorem

When the base is 9ft from the wall, this means that:

x = 9

Substitute 9 for x and 10 for L in L^2 = x^2 + y^2

10^2 = 9^2 + y^2

100 = 81 + y^2

Make y^2 the subject

y^2 = 100 - 81

y^2 = 19

Make y the subject

y = \sqrt{19

y = 4.36

<em>Hence, the true distance at that point is approximately 4.36ft</em>

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An observer sitting at a bus stop sees the bus drive by at 30 m/s to the east. He also sees a
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32 m/s

Explanation:

The speed of a bus is 30 m/s due East wrt the passenger

He also sees a  passenger on the bus walking to the back at 2 m/s.

We need to find the passenger's velocity relative  to the bus. As the observer sees that the bus and the passenger are moving in opposite direction. Let v is the relative velocity. So,

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Hence, the passenger's velocity relative  to the bus is 32 m/s.

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4 years ago
In what ways water helps in germination?​
quester [9]

Answer:

Water can spread germs through bacteria.

Explanation:

Bacteria can live in water and can spread to new locations when water is moved.

6 0
3 years ago
What is the energy released in this B- nuclear reaction 2K-&gt; 2Ca0,e? (The atomic mass of 42 K is 41.962403 u and that of 42Ca
Katyanochek1 [597]

<u>Answer:</u> The energy released in the given nuclear reaction is 3.526 MeV.

<u>Explanation:</u>

For the given nuclear reaction:

_{19}^{42}\textrm{K}\rightarrow _{20}^{42}\textrm{Ca}+_{-1}^{0}\textrm{e}

We are given:

Mass of _{19}^{42}\textrm{K} = 41.962403 u

Mass of _{20}^{42}\textrm{Ca} = 41.958618 u

To calculate the mass defect, we use the equation:

\Delta m=\text{Mass of reactants}-\text{Mass of products}

Putting values in above equation, we get:

\Delta m=(41.962403-41.958618)=0.003785u

To calculate the energy released, we use the equation:

E=\Delta mc^2\\E=(0.003785u)\times c^2

E=(0.003785u)\times (931.5MeV) (Conversion factor: 1u=931.5MeV/c^2 )

E=3.526MeV

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4 years ago
Beams of high-speed protons can be produced in "guns" using electric fields to accelerate the protons. A certain gun has an elec
Natasha2012 [34]

Answer: v = 2.75 * 10^7 m/s

Explanation: Since the electric field is a uniform one and the distance is small, the motion of the electron is of a constant acceleration, hence newton's laws of motion is applicable.

From the question

E=strength of electric field = 214N/c

q=magnitude of an electronic charge = 1.609* 10^-16c

m= mass of an electronic charge = 9.11*10^-31kg

v = velocity of electron.

S= distance covered = 1cm = 0.01m

a = acceleration of electron.

F = ma but F=Eq

Eq = ma.

a = Eq/m

a = 214 * 1.609*10^-16/ 9.11 * 10^-31

a = 344.32 * 10^-16/ 9.11 * 10 ^-31

a = 3. 779* 10^16 m/s²

Before the electron is accelerated, they are always not moving, hence initial velocity (u) = 0.

By using the equation of motion, we have

v² = u² + 2aS

But u = 0

v² = 2aS

v²= 2* 3.779*10^16 * 0.01

v² = 7.558 * 10^14

v = √7.558 * 10^14

v = 2.75 * 10^7 m/s.

6 0
3 years ago
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