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Luba_88 [7]
2 years ago
15

A student is trying to solve the system of two equations given below:

Mathematics
2 answers:
gogolik [260]2 years ago
7 0

Step-by-step explanation:

as the following pic answer should be × -2

ser-zykov [4K]2 years ago
7 0

Answer:

O -2(x+y=8)

Step-by-step explanation:

If you put the problems beside each other, they look like this;

2x + 5y = 24

  x + y = 8

So you are trying to find a way to simplify the x's

Step 1;

See if there are any numbers that you could multiply to the bottom problem that would help you get rid of the x specifically.

In this case, -2 would cancel out that other 2 right? Because if you added them, they cancel each other out; 2 -2 = 0

Step 2:

if you multiply, you have to do it to the entire problem;

-2(x + y = 8)    (-2 times x, -2 times y, -2 times 8)

-2x + -2y = -16

Step 3:

Go back to your original problem and work it out;

2x + 5y = 24

-2x + -2y = -16

2x and -2x cancel each other out so now you only have;

5y = 24

-2y = -16

Step 4:

Combine like terms;

5y = 24

-2y = -16

3y = 8

Divide by 3

y = 2.6

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4. The range is -2 ≤ y ≤ 4

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Step-by-step explanation:

* Lets explain how to solve the problem

# Question 4:

- The range of the function is the values of all y (output) which is

 corresponding to the values of all x (input)

- The figure is a stare, the values of x is from -4 to 4

∴ The domain is -4 ≤ x ≤ 4

- The corresponding values of y are from -2 to 4

∴The range is -2 ≤ y ≤ 4

# Question 5:

- The table represent a relation between x and y

- x is the input of the relation

- y is the output of the relation

∵ The input of the relation is called the domain of it

∴ The domain of the relation is all values of x in the table

- the values of x are -2 , -1 , 0 , 3.5 , 4.2

∴ The domain is {-2 , -1 , 0 , 3.5 , 4.2}

# Question 6:

- The relation can be a function if each ordered pair has a

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- That means every x (input) has only one y (output)

- Ex : The relation {(a , b) , (c , d) , (a , f)} is not a function because

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∵ The relation is {(-4 , 0) , (-3 , 0) , (-2 , 1) , (1 , -2) , (-3 , 4)}

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Also,

\begin{gathered} \text{ From the given image, the value of the right limit of f at x=1 } \\ \lim_{x\to a^+}f(x)\gt1 \end{gathered}

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