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2 years ago

What system of equations would you use to solve the problem below?

Mathematics

1 answer:

EleoNora [17]2 years ago

4 0

Let x be multiple-choice questions
Let y be short-answer questions

x + y = 28

3x + 5y = 100

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A box in the shape of a rectangular prism has a width that is 5 inches greater than the height and a length that is 2 inches gre

aliina [53]

The volume of the rectangular prism can be express in standard polynomial as follows:

x³ + 12x² + 35x

<h3>How to find the volume of a rectangular prism?</h3>

volume of a rectangular prism = lwh

where

l = length
w = width
h = height

Therefore,

let

height = x

width = x + 5

length = x + 5 + 2 = x + 7

Therefore,

volume = x(x + 5)(x + 7)

volume = x(x² + 7x + 5x + 35)

volume = x(x² + 12x + 35)

volume = x³ + 12x² + 35x

learn more on volume here: brainly.com/question/2005063

#SPJ1

7 0

2 years ago

PLEASE HELP ASAP!!!!!!

solmaris [256]

the answer would be x=6

to find it you would set 3x-2 equal to 2x+4 and solve because the two sides would be equal if the triangles are congruent

hope this helps :)

4 0

3 years ago

Read 2 more answers

Help me solve this please

Rzqust [24]

Answer:

B. g is Greater or equal to 64

6 0

4 years ago

Read 2 more answers

Abigail has decided to examine her checking account statements. Last month's account balance was $74. This month, ot is $37. Wha

Anna [14]

Answer: -50%

37 x 2 = 74

5 0

3 years ago

Read 2 more answers

A machine has four components, A, B, C, and D, set up in such a manner that all four parts must work for the machine to work pro

olchik [2.2K]

Answer:

0.756

Step-by-step explanation:

It is given that a machine has four components, A, B, C, and D.

$P(A)=P(B)=0.93, P(C)=0.95,P(D)=0.92$

If these components set up in such a manner that all four parts must work for the machine to work properly.

We need to find the probability that the machine works properly. It means we have to find the value of $P(A\cap B\cap C\cap D)$ .

If two events X and Y are independent, then

$P(X\cap Y)=P(X)\times P(Y)$

Assume the probability of one part working does not depend on the functionality of any of the other parts.

$P(A\cap B\cap C\cap D)=P(A)\times P(B)\times P(C)\times P(D)$

Substitute the given values.

$P(A\cap B\cap C\cap D)=0.93\times 0.93\times 0.95\times 0.92$

$P(A\cap B\cap C\cap D)=0.7559226$

$P(A\cap B\cap C\cap D)\approx 0.756$

Therefore, the probability that the machine works properly is 0.756.

7 0

3 years ago