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2 years ago

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Mathematics

2 answers:

amm18122 years ago

8 0

Answer: A) Point B, because if cups of frosting are 50, then drops of food coloring will be 200.

This is because the proportion of frosting to food coloring is 1:4, and if the answer to A is simplified (50:200), the ratio would be the same.

stepladder [879]2 years ago

8 0

Answer:

Option A. will be the answer.

Step-by-step explanation:

From the given table we will find the relation first and the we will try to find the point with the same relation in the graph.

From the given table ratio of Cups of frosting and Drops of food color is = $\frac{\text{Cups of frosting}}{\text{Drops of food color}}$

= $\frac{2}{8}$

= $\frac{1}{4}$

Or 1 : 4

Now the point B shows the ratio between food color and frosting = $\frac{\text{Cups of frosting}}{\text{Drops of food color}}$

= $\frac{\text{x-coordinates}}{\text{y-coordinates}}$

= $\frac{50}{200}$

= $\frac{1}{4}$

The same ratio 1 : 4

Option A. will be the answer.

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Nolan used the following procedure to find an estimate for StartRoot 18 EndRoot.

stiks02 [169]

Answer:

Nolan correctly identified the square numbers before and after 18.

The square roots of them are 4 and 5.

Clearly, square root of 18 should lie between 4 and 5 only.

He, then carefully squared 4.1, 4.2, 4.3 etc. and identified that 4.3 squared is nearer to 18.

Since, Nolan is finding estimated square root, his steps are cool and he didn't make any error.

4 0

2 years ago

Read 2 more answers

Suppose that the population of the scores of all high school seniors who took the SAT Math (SAT-M) test this year follows a Norm

Vlad1618 [11]

Answer:

Confidence = $1-\alpha=1-0.01=0.99$

And then the confidence level would be given by 99%

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma)$

The distribution for the sample mean is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\bar x =512$ represent the sample mean

$\sigma=100$ represent the population standard deviation

n= 100 sample size selected.

The confidence interval is given by this formula:

$\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$ (1)

The marginof error for this case is given by Me=25.76. And we know that the formula for the margin of error is given by:

$Me=z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

$25.76=z_{\alpha/2} \frac{100}{\sqrt{100}}$

And we can find the critical value $z_{\alpha/2}$ like this:

$z_{\alpha/2}=\frac{25.76(\sqrt{100})}{100}=2.576$

And we know that on the right tail of the z score =2.576 we have $\alpha/2$ of the total area. We can find the area on the right of the z score using this excel code:

"=1-NORM.DIST(2.576,0,1,TRUE)" or using a table of the normal standard distribution, and we got 0.004998= $\alpha/2$ , so then $\alpha=0.00498*2=0.009995 \approx 0.01$ , and then we can find the confidence like this: