Answer:
The speed of molecules in an "ideal" gas is related to the temperature
Advanced work indicates that
1/2 m v^2 = 3/2 k T where v^2 here is the mean square speed
This is true for H2, He, O2, Hg etc. and m is the molecular mass and k the Boltzmann constant
If we consider Boyles law for gases, it states the following equation,
PV/T =k
where k is a constant
P-pressure, T- temperature and V -volume
the volume is constant at both situations as its a rigid tank as mentioned in the questions.
Therefore we consider Volume to be constant , then equation is
P/T = kV
kV = c (new constant)
P/T = c
P = cT
Therefore pressure is inversely proportional to temperature, whatever change in pressure would cause the same kind of change in temperature as well.
therefore when T decreases, P also decreases.
Answer is B
Answer:
The root pass is made with a 5/32” (4.0mm) diameter electrode. A cellulosic electrode (E-XX10) is being used. The root pass is welded with reverse (DC+) polarity.
Explanation:
Answer:
Th steps is as shown in the attachment
Explanation:
from the diagram, its indicates that twelve identical charges are distributed evenly on the circumference of the circle. assuming one of gthe charge is shifted to the centre of he circle alomng the x axis, as such the charge is unbalanced and there is need ot balanced all the identical charges for the net force to be equal to zero.
The mathematical interpretation is as shown in the attachment.
Answer: 17.5N
Explanation:
Given that,
spring constant (k) = 70N/m
Original length (lo) = 40 cm
New length (ln) = 15 cm
extension of spring (e) = new length - original length
i.e e = ln - lo
e = 15 cm - 40 cm
e = -25cm (the negative sign is negligible, just the same magnitude matters)
So, convert 25cm to metres
If 100cm = 1m
25cm = 25/100 = 0.25m
(Note that how hard the spring push refers to the Force, hence, find force.)
Now, apply the Hooke law (F = ke)
Force = spring constant x extension
F = 70N/m x 0.25m
F = 17.5N
Thus, the spring push with a force of 17.5N when compressed.