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Dmitry [639]
3 years ago
15

A computer technician always touches the metal body of a computer before touching any of its electrical parts. why?

Physics
1 answer:
Nikolay [14]3 years ago
6 0

Answer:

Computer technician always touch the metal body parts of the computer before touch any electrical part of the computer because it will neutralized the body static charge.

The components of the computer are made up of the materials with the positive and negative charge electron and their electric effect basically neutralized the one another.

while touching any electrical hardware make sure that the electricity is off and discharge our body from any static charge. Also avoid wearing wool clothes when touching any electrical hardware parts as they also build static charge.  

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Which of the following statements apply to electric charges?
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Answer:

The statement "If a positively charged rod is brought close to a positively charged object, the two objects will repel " applies to electric charges.

Explanation:

There are only two types of electric charges. Both having own magnitude but different charge.

1. Positive charge

2. Negative charge

Like charges repel each other and opposite charges always attract each other.

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A lad, waiting for his friend walks in the sidewalk, in front of her house, from the front door, first, he moves towards the Pos
Andreas93 [3]

His total displacement from his original position is -1 m

We know that total displacement of an object from a position x to a position x', d = final position - initial position.

d = x' - x

If we assume the lad's initial position in front of her house is x = 0 m. The lad then moves towards the positive x-axis, 5 m. He then ends up at x' = 5 m. He then finally goes back 6 m.

Since displacement = final position - initial position, and his displacement is d' = -6 m (since he moves in the negative x - direction or moves back) from his initial position of x' = 5 m.

His final position, x" after moving back 6 m is gotten from

x" - x' = -6 m

x" = -6 + x'

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x" = -1 m

Thus, his total displacement from his original position is

d = final position - initial position

d = x" - x

d = -1 m - 0 m

d = -1 m

So, his total displacement from his original position is -1 m

Learn more about displacement here:

brainly.com/question/17587058

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