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3 years ago

Which change occurs when an atom undergoes decay?

1 answer:

6 0

<span>When an atom undergoes decay its nucleus becomes unstable because it does not have a balance of neurons and protons. This means the atoms try to find a confirmation in which it is stable. In doing so, it is possible that the atom changes its element, and it frees a huge amount of energy in order to balance itself. This is the base of radioactivity.</span>

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How much heat (in kJ) is needed to convert 866 g of ice at −10°C to steam at 126°C? (The specific heats of ice and steam are 2.0

elena-14-01-66 [18.8K]

Answer:

2671.3 kJ

Explanation:

m = 866 g at - 10 degree C converts into steam at 126 degree C.

The following steps are there

(1) ice at - 10 degree C converts into ice at 0 degree C

H1 = m x specific heat of ice x ΔT

H1 = 866 x 2.03 x 10 = 17579.8 J

(ii) ice at 0 degree C converts into water at 0 degree C

H2 = m x Latent heat of fusion = 866 x 334 = 289244 J

(iii) water at 0 degree C converts into water at 100 degree C

H3 = m x specific heat of water x ΔT

ΔH3 = 866 x 4.186 x 100 = 362507.6 J

(iv) water at 100 degree C converts into steam at 100 degree C

H4 = m x Lateant heat of vaporisation

H4 = 866 x 2260 = 1957160 J

(v) seam at 100 degree C converts into steam at 126 degree C

H5 = m x specific heat of steam x ΔT

H5 = 866 x 1.99 x 26 = 44806.84 J

The total heat required is

H = H1 + H2 + H3 + H4 + H5

H = 2671298.24 J = 2671.3 kJ

8 0

3 years ago

Kathy had a heavy metal ball and Rich had a light wooden ball they drop the balls from the same height. they were surprised to d

Colt1911 [192]

Answer: I scored a 9/10

Explanation:

I agree with Kathy gravity must be acting the same on both balls just because one ball is heavier doesn’t mean they will hit different times if the wooden ball was drop closer to the ground then the wooden ball would hit the ground first

3 0

3 years ago

Constant power P is delivered to a car of mass m by its engine. Show that if air resistance can be ignored, the distance covered

olga2289 [7]

Answer:

Check Explanation.

Explanation:

At rest, the car had zero kinetic energy, that is K(rest) = 0. The kinetic energy of the car when the car moved, k(moved) can be calculated by using the work- energy relationship that is;

Work, W= k(moved) - k(rest).

k(moved) = work, W + k(rest).

[Recall that k(rest) = 0]. Therefore, k(moved) = work, W.

{Two Important equations to note are (1). Work, W=( 1/2) mass,m × (speed, V)^2 and (2). Power, P = work,W/ time,t}.

Hence, k(moved) = ( 1/2) mass,m × (speed, V)^2 ---------------------------(1).

Since, power, P= W/t -----------------(2).

Then, equation (2) becomes;

Power, P = m × v^2/ 2 × t.

Making, speed, v the subject of the formula, we have;

v = [(2 × P × t)/ m]^ 1/2. ---------------(3).

Another thing we have to remember is the formula for speed which is the change in distance with time that is; ds/ dt.

Therefore, ds/ dt = [(2 × P × t)/ m]^ 1/2.