Hey there!
Density = 2.67 g/cm³
volume = 30.5 mL
Mass = density *volume
Mass = 2.67 * 30.5
Mass = 81.435 g
Therefore:
Mass in kg :
1 kg -------------- 1000 g
?? ----------------- 81.435 g
mass = 81.435 * 1 / 1000
mass = 0.081435 kg
Answer:
A mixture!
Explanation:
Mixtures are a substance made of combining two or more different kinds of matter :)
Hope this helped!
The kind of magma that is found in the most explosive volcanoes, the composite volcanoes, is andesitic magma. It is magma that is quite high in silica content which makes it thick, sticky and gooey. Great lumps of this sticky magma cool at the top of the volcano to form a sealed cap. Magma beneath the cap builds up and pressure mounts and eventually becomes too much to be contained and the magma violently erupts out from the top, blowing out the cap and shooting miles up into the air and in all directions.
The kind of magma found in gentle volcanoes such as shield volcanoes is runny in consistency. It has very minimal amounts of silica and is not thick but loose. It therefore tends to trickle out of the top of the volcano rather than erupt or explode.
Answer:
Molarity = 0.95 mol/dm³
Explanation:
Given data:
Volume of H₂SO₄ = 15.8 cm³
Volume of NaOH = 20 cm³
Concentration of NaOH = 1.5 mol/dm³
Concentration of H₂SO₄ = ?
Solution:
Chemical equation:
NaOH + H₂SO₄ → Na₂SO₄ + H₂O
First of all we will calculate the number of moles of NaOH and for that we will convert the units first,
Volume = 20 cm³/1000 = 0.02 L
Concentration of NaOH = 1.5 mol/dm³
1 mol/dm³ = 1 mol/L
Concentration of NaOH = 1.5 mol/L
Number of moles of NaOH:
Molarity = number of moles / volume in L
1.5 M = number of moles / 0.02 L
Number of moles = 1.5 M ×0.02 L
Number of moles = 0.03 mol
Now we will compare the moles of NaOH and H₂SO₄
NaOH : H₂SO₄
2 : 1
0.03 : 1/2×0.03 = 0.015 mol
Concentration of H₂SO₄:
Volume of H₂SO₄:
15.8 cm³/1000 = 0.0158 L
Molarity = number of moles / volume in L
Molarity = 0.015 mol / 0.0158 L
Molarity = 0.95 mol/L
1 mol/L = 1 mol/dm³
Molarity = 0.95 mol/dm³
