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3 years ago

Substances that are physical combinations of two or more different types of matter are known as

Chemistry

1 answer:

Veseljchak [2.6K]3 years ago

7 0

Answer:

A mixture!

Explanation:

Mixtures are a substance made of combining two or more different kinds of matter :)

Hope this helped!

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What are some examples of forced convection

Nezavi [6.7K]

Answer: Using a fan on a hot summer day. Explanation: the sweat that our body produces is for effective heat transfer. ...

Radiators in fridges, acs and automobiles. ...

Instant water heating geysers or any other geysers.

Explanation:

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3 years ago

How many moles of Cu(OH)2 will be produced if given 1 mole KOH.

stiks02 [169]

Answer:

0.032 mole

Explanation:

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1 year ago

The acid HOCl (hypochlorous acid) is produced by bubbling chlorine gas through a suspension of solid mercury(II) oxide particles

sergejj [24]

Answer: The expression for equilibrium constant is $K_{eq}=\frac{[HOCl]^2}{[H_2O][Cl_2]^2}$

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{eq}$

For the general chemical equation:

$aA+bB\rightleftharpoons cC+dD$

The expression for $K_c$ is given as:

$K_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

For the given chemical reaction:

$2HgO(s)+H_2O(l)+2Cl_2(g)\rightleftharpoons 2HOCl(aq.)+HgO.HgCl_2(s)$

The expression for $K_{eq}$ is given as:

$K_{eq}=\frac{[HOCl]^2[HgO.HgCl_2]}{[HgO]^2[H_2O][Cl_2]^2}$

The concentration of solid is taken to be 0.

So, the expression for $K_{eq}$ is given as:

$K_{eq}=\frac{[HOCl]^2}{[H_2O][Cl_2]^2}$

3 0

3 years ago

Which ones are physical change and which ones are chemical reactions:

Sonbull [250]

Physical change- evaporation , condensation
Chemical change- combustion , neutralization

8 0

1 year ago

If 0.2 g of nitrobenzene are added to 10.9 g of naphthalene, calculate the molality of the solution. (given: molar mass of nitro

In-s [12.5K]

Molality is defined as 1 mole of a solute in 1 kg of solvent.

Molality=

$\frac{Number of moles of solute}{Mass of solvent in kg}$

Number of moles of solute, n=

$\frac{Given mass of the substance}{Molar mass of the substance}$

Given mass of the nitrobenzene=0.2 g

Molar mass of the substance= 123.06 g mol⁻¹

Number of moles of nitrobenzene,

$n= \frac{0.2 }{123.06}$

Number of moles of nitrobenzene, n= 0.0016 mol

Mass of 10.9 g of naphthalene in kg=0.0109

$Molality= \frac{0.0016}{0.0109 }$

Molality= 0.146 m

7 0

3 years ago