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2 years ago

Reflection across the y-axis

Mathematics

1 answer:

Anit [1.1K]2 years ago

8 0

Answer:

A reflection of a point over the y -axis is shown. The rule for a reflection over the y -axis is (x,y)→(−x,y) .

Step-by-step explanation:

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How will the parabola transform?

Anon25 [30]

A and c are the answers.

5 0

3 years ago

A roller coaster has four cars each with the same number of seats. these are 21 passengers seated in the roller coaster, but 3 s

belka [17]

Given:

Number of passengers seated in the roller coaster = 21

Empty seats = 3

Number of cars in roller coaster = 4 (each with the same number of seats)

To find:

An equation that can be used to determine the number of seats in each car.

Solution:

Let s be the number of seats in each car.

Total number of seats in 4 cars = 4s

Using the given information,

Total number of seats = Occupied seated + Empty seats

= 21 + 3

= 24

Now, the required equation is

$4s=24$

Therefore, the required equation is $4s=24$ .

Divide both sides by 4.

$s=\dfrac{24}{4}$

$s=6$

Therefore, the number of seats in each car is 6.

6 0

3 years ago

An equation that defines y as a function of x is given. Solve for y in terms of x, and replace y with the function notation f(x)

34kurt

Answer:C

Step-by-step explanation:

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4 years ago

What is the constant of proportionality in this graph?

lana [24]

Answer:

one half or 1/2

Step-by-step explanation:

do your rise over your run on the graph.

7 0

3 years ago

The probability density function of the time to failure of an electronic component in a copier (in hours) is f(x) for Determine

salantis [7]

The question is incomplete. Here is the complete question.

The probability density function of the time to failure of an electronic component in a copier (in hours) is

$f(x)=\frac{e^{\frac{-x}{1000} }}{1000}$

for x > 0. Determine the probability that

a. A component lasts more than 3000 hours before failure.

b. A componenet fails in the interval from 1000 to 2000 hours.

c. A component fails before 1000 hours.

d. Determine the number of hours at which 10% of all components have failed.

Answer: a. P(x>3000) = 0.5

b. P(1000<x<2000) = 0.2325

c. P(x<1000) = 0.6321

d. 105.4 hours

Step-by-step explanation: <em>Probability Density Function</em> is a function defining the probability of an outcome for a discrete random variable and is mathematically defined as the derivative of the distribution function.

So, probability function is given by:

P(a<x<b) = $\int\limits^b_a {P(x)} \, dx$

Then, for the electronic component, probability will be:

P(a<x<b) = $\int\limits^b_a {\frac{e^{\frac{-x}{1000} }}{1000} } \, dx$

P(a<x<b) = $\frac{1000}{1000}.e^{\frac{-x}{1000} }$

P(a<x<b) = $e^{\frac{-b}{1000} }-e^\frac{-a}{1000}$

a. For a component to last more than 3000 hours:

P(3000<x<∞) = $e^{\frac{-3000}{1000} }-e^\frac{-a}{1000}$

Exponential equation to the infinity tends to zero, so:

P(3000<x<∞) = $e^{-3}$

P(3000<x<∞) = 0.05

There is a probability of 5% of a component to last more than 3000 hours.

b. Probability between 1000 and 2000 hours:

P(1000<x<2000) = $e^{\frac{-2000}{1000} }-e^\frac{-1000}{1000}$

P(1000<x<2000) = $e^{-2}-e^{-1}$

P(1000<x<2000) = 0.2325

There is a probability of 23.25% of failure in that interval.

c. Probability of failing between 0 and 1000 hours:

P(0<x<1000) = $e^{\frac{-1000}{1000} }-e^\frac{-0}{1000}$

P(0<x<1000) = $e^{-1}-1$

P(0<x<1000) = 0.6321

There is a probability of 63.21% of failing before 1000 hours.

d. P(x) = $e^{\frac{-b}{1000} }-e^\frac{-a}{1000}$

0.1 = $1-e^\frac{-x}{1000}$

$-e^{\frac{-x}{1000} }=-0.9$

${\frac{-x}{1000} }=ln0.9$

-x = -1000.ln(0.9)

x = 105.4

10% of the components will have failed at 105.4 hours.

5 0

4 years ago