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qaws [65]
3 years ago
11

Please help I have 2 questions.

Mathematics
1 answer:
Llana [10]3 years ago
7 0
1) 3 x 35
=105 inches

105/12
= 8.75 feet

2) 7x80
= 560mm
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Someone help 6th grade math i will give brainliest
Soloha48 [4]
The first one is 64. The second one is -64. Third is 10000
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Zach has an above-ground pool that has a radius of 5.5 feet. He wants to put a new wall liner around his pool and needs to know
Tems11 [23]

Answer: 34.54feet

Step-by-step explanation:

Thw circumference of the pool will be calculated by using the formula:

= 2πr

where

π = 3.14

r = 5.5

Therefore, circumference = 2πr

= 2 × 3.14 × 5.5

= 34.54feet

Therefore, the circumference of the pool to the nearest hundredth is 34.54feet.

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3 years ago
If a cone has a volume of 121cm^3 and a radius of 5 cm, how tall is it
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16. David wanted to buy a new suit selling for $400. He negotiated with the salesperson
Reil [10]
Answer:$344

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7 0
2 years ago
If a/b &lt; c/d with b &gt; 0, d &gt; 0, prove that a+c / b+d lies between the two fractions a/b and c/d .​
Tems11 [23]

Divide through everything by <em>b</em> :

\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}

Since <em>a/b</em> < <em>c/d</em>, it follows that

\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}

Multiply through everything on the right side by <em>b/d</em> to get

\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd

and so (<em>a</em> + <em>c</em>)/(<em>b</em> + <em>d</em>) < <em>c/d</em>.

For the other side, you can do something similar and divide through everything by <em>d</em> :

\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}

and <em>a/b</em> < <em>c/d</em> tells us that

\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}

Then

\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab

and so (<em>a</em> + <em>c</em>)/(<em>b</em> + <em>d</em>) > <em>a/b</em>.

Then together we get the desired inequality.

5 0
3 years ago
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