For congruence of triangles.
If;
Then the corresponding sides and angles will be equal.
Only the above congruence statements are true.
Any options that has any of the above congruence statement is true.
<h3>
Answer: Choice C) x^4 - 2</h3>
Explanation:
If the exponent is negative, then that means we apply the reciprocal. So something like x^(-2) becomes 1/(x^2). A polynomial cannot have a variable in the denominator like this. So we can rule out choices A, B, and D. Choice C is the only thing left. It is a polynomial because the exponent is a positive whole number.
Answer:
B
Step-by-step explanation:
Let’s first look at the y-intercept. Since the equation is in y = mx + b form, we know that m is the slope and b is the y-intercept, so the slope is 1/2 and the y-intercept is 2, or (0,2). We can narrow down our search by noticing that C and D don’t intersect (0,2). That leaves A and B.
The slope is calculated by (y_1 - y_2)/(x_1 - x_2) given points (x_1, y_1) and (x_2, y_2). The slope for A is (4-0)/(2-(-2)) = 4/4 = 1 and the slope for B is (2-0)/(0-(-4)) = 2/4 = 1/2. The slope of B matches the slope that we are looking for. So, the answer is B.
Answer:
x = -40
Step-by-step explanation:
First we distribute
5x + 35 + 2 = 4x - 4 + 1
Collect like terms
5x + 37 = 4x - 3
Subtract 37 from both sides
5x = 4x - 40
Subtract 4x from both sides
1x = -40 OR x = -40
Answer:
We are given that angle AOB is a central angle of circle O and that angle ACB is a circumscribed angle of circle O. We see that AO ≅ BO because
✔ all radii of the same circle are congruent.
We also know that AC ≅ BC since
✔ tangents to a circle that intersect are congruent.
Using the reflexive property, we see that
✔ side CO is congruent to side CO.
Therefore, we conclude that △ACO is congruent to △BCO by the
✔ SSS congruence theorem.
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