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JulsSmile [24]
4 years ago
13

What are factors of 27?

Mathematics
2 answers:
qwelly [4]4 years ago
7 0
The factors of 27 are
1 27
3 9
Artyom0805 [142]4 years ago
6 0
The answer would be 3^33
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Please help and show work thank you.
vichka [17]
An equilateral triangles has 3 equal sides and 3 equal angles.
All the angles of an equilateral triangle have a measure of 60 degrees.

Using the Pythagorean theorem, the length of the hypotenuse squared is the length of one leg squared plus the length of another leg squared.

Here's the equation for the Pythagorean theorem.
Let c be the length of the hypotenuse.
Let a and b be the length of the two legs.
a^2 + b^2 = c^2 

Have an awesome day! :)
7 0
3 years ago
Read 2 more answers
Which should equal 105 to prove that f // g ? <br><br> A<br> B<br> C<br> D <br> Please hurry !!
frosja888 [35]

since you have the 75, we know that a would equal 105 for line g , since a line = 180 degrees

 so to make line f parallel with g it needs the same angles with line n as line g has

so if a = 105, then angle d would also need to be 105

 The answer is D

3 0
3 years ago
Read 2 more answers
How many solutions does the following equation have?
Masteriza [31]

Answer:

One solution

Step-by-step explanation:

Hi,

3(x + 5) = -4x + 8

3x + 15 = -4x + 8

7x + 15 = 8

7x = -7

x = -1

One solution :)

8 0
3 years ago
Read 2 more answers
Which of the following best describes the slope of the line below?
atroni [7]

Answer:

Zero

Step-by-step explanation:

Since the line is a horizontal line, the slope does not change.  The slope is zero.

8 0
2 years ago
Read 2 more answers
A government report gives a 99% confidence interval for the proportion of welfare recipients who have been receiving welfare ben
juin [17]

Answer:

The estimation for the proportion for this case is \hat p = 0.21

And we know that the 99% confidence interval is given by:

0.21 \pm 0.045

So then the margin of error at 99% of confidence is 0.045, and the margin of error is given by this formula:

ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

If we decrease the confidence level this margin of error can't be higher than 0.045 so then the correct answer for this case would be:

d. 21% ± 4.8%

Because if the z value decrease from 2.58 to 1.96 not makes sense that the margin of error increase from 0.045(4.5%) to 0.048(4.8%)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

The confidence interval would be given by this formula  

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.96

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=2.58

The estimation for the proportion for this case is \hat p = 0.21

And we know that the 99% confidence interval is given by:

0.21 \pm 0.045

So then the margin of error at 99% of confidence is 0.045, and the margin of error is given by this formula:

ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

If we decrease the confidence level this margin of error can't be higher than 0.045 so then the correct answer for this case would be:

d. 21% ± 4.8%

Because if the z value decrease from 2.58 to 1.96 not makes sense that the margin of error increase from 0.045(4.5%) to 0.048(4.8%)

5 0
3 years ago
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