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2 years ago

Would young rocks be found near a volcano?

Physics

1 answer:

Setler [38]2 years ago

8 0

Answer:

maybe

Explanation:

young rocks may be found near volcanoes

You might be interested in

Which machine can create images of atoms?

Svetradugi [14.3K]

Answer: Scanning Tunneling Microscope

Explanation:

The answer is, of course, the greatest Star Trek fan art imaginable: images literally built out of individual atoms. The images are the work of IBM scientists who created the unique artwork with a two-ton machine called the Scanning Tunneling Microscope that moves single atoms across a tiny piece of copper.

6 0

3 years ago

A ball is thrown straight up with a speed of 30

konstantin123 [22]

Answer:

A ball is thrown straight up with a speed of 30

m/s. What is the maximum height reached by

the ball?

4 0

3 years ago

The gravitational force between two objects is 2400 N. What will be the gravitational force between the objects if the mass of o

motikmotik

Answer:

4800N

Explanation:

Lets assume,

Mass of first object = m₁

Mass of second object = m₂

Distance between the two objects = r

Thus the force between the two objects will be

$F = \frac{G\times m_{1}\times m_{2}}{r^{2}}$

where, G = Universal gravitational constant

Given, F = 2400N

New mass of second object = 2m₂

Now, the force will be

$F_{2} = \frac{G\times m_{1}\times 2m_{2}}{r^{2}}$

$F_{2}= 2\frac{G\times m_{1}\times m_{2}}{r^{2}}$

$F_{2}= 2F$

$F_{2}= 2\times2400$

Thus, F₂ = 4800N

6 0

3 years ago

A 100 Kg man is diving off a 50 meter cliff. What is his kinetic energy when he is 20 meters from the water?

iren2701 [21]

Answer:

$K.E=29.403125J$

Explanation:

From the question we are told that

Mass $M=100$

Height $50-20=30m$

Generally the equation for velocity before impact is is is mathematically given by

$v=\sqrt{2gh}$

$v=\sqrt{2*9.8*30}$

$v=24.25$

Generally the equation for Kinetic Energy is is mathematically given by

$K.E=\frac{1}{2}mv^2$

$K.E=\frac{1}{2}*100*(24.25)^2\\$

$K.E=29403.125J$

$K.E=29.403125J$

8 0

3 years ago

A 1000 kg car moving a 10 m/s collides with a stationary 2000 kg truck. The two vehicles interlock as a result of the collision.

IgorLugansk [536]

Answer:

v₃ = 3.33 [m/s]

Explanation:

This problem can be easily solved using the principle of linear momentum conservation. Which tells us that momentum is preserved before and after the collision.

In this way, we can propose the following equation in which everything that happens before the collision will be located to the left of the equal sign and on the right the moment after the collision.

$(m_{1}*v_{1})+(m_{2}*v_{2})=(m_{1}+m_{2})*v_{3}$

where:

m₁ = mass of the car = 1000 [kg]

v₁ = velocity of the car = 10 [m/s]

m₂ = mass of the truck = 2000 [kg]

v₂ = velocity of the truck = 0 (stationary)

v₃ = velocity of the two vehicles after the collision [m/s].

Now replacing:

$(1000*10)+(2000*0)=(1000+2000)*v_{3}\\v_{3}=3.33[m/s]$

7 0

3 years ago