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NemiM [27]
3 years ago
8

The chart shows data for four moving objects.

Physics
1 answer:
vesna_86 [32]3 years ago
5 0

Answer:

Y

Explanation:

by adding all the numbers

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Picture attached please help! 2 different questions!
Maksim231197 [3]

Wave A would have higher amplitude

Hope this helps :D

7 0
3 years ago
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A standing wave of the third overtone is induced in a stopped pipe, 2.5 m long. The speed of sound is The frequency of the sound
NemiM [27]

Answer:

f3 = 102 Hz

Explanation:

To find the frequency of the sound produced by the pipe you use the following formula:

f_n=\frac{nv_s}{4L}

n: number of the harmonic = 3

vs: speed of sound = 340 m/s

L: length of the pipe = 2.5 m

You replace the values of n, L and vs in order to calculate the frequency:

f_{3}=\frac{(3)(340m/s)}{4(2.5m)}=102\ Hz

hence, the frequency of the third overtone is 102 Hz

8 0
3 years ago
A scientist heats flexible container full of neon gas .what will most likely happen to the container as the gas absorbs heat
Ilia_Sergeevich [38]
As the container starts to heat up, so will the neon gas. Heat is nothing but energy, and when you add energy to a gas, it will start vibrating much faster and hit the edges of the container at a higher rate and a faster velocity. Therefore, it's possible to deduce that the container will most likely rupture and/or "explode". 
4 0
3 years ago
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Three long wires are connected to a meter stick and hang down freely. Wire 1 hangs from the 50-cm mark at the center of the mete
disa [49]

Answer:

Three long wires are connected to a meter stick and hang down freely. Wire 1 hangs from the 50-cm mark at the center of the meter stick and carries 1.50 A of current upward. Wire 2 hangs from the 70-cm mark and carries 4.00 A of current downward. Wire 3 is to be attached to the meterstick and to carry a specific current, and we want to attach it at a location that results ineach wire experiencing no net force.

(a) Determine the position of wire 3.

b) Determine the magnitude and direction of current in wire 3

Explanation:

a) F_{net} \text {on wire }3=0

\frac{\mu_0 I_1 I_3}{2 \pi x} = \frac{\mu I_2 I_3}{2 \pi (0.2+x)} \\\\\frac{1.5}{x} =\frac{4}{0.2+x} \\\\0.03+1.5x=4x\\\\x=0.012m\\\\=1.2cm

position of wire = 50 - 1.2

= 48.8cm

b)  F_{net} \text {on wire }1=0

\frac{\mu _0 I_1 I_3}{2 \pi (1.2)} = \frac{\mu _0 I_1 I_2}{2 \pi (20)} \\\\\frac{I_3}{1.2} =\frac{4}{20} \\\\I_3=0.24A

Direction ⇒ downward

5 0
3 years ago
The case of Allan v. Adam was tried first in a court of first instance. The case was appealed to the intermediate state court of
mezya [45]
There are no more courts of appeal within the state system.
6 0
3 years ago
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