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antiseptic1488 [7]
3 years ago
10

The main part of the nuclear power plant is the ____. Where nuclear ____ reactions take place.

Physics
2 answers:
emmasim [6.3K]3 years ago
7 0
Turbine an unclean fission
chubhunter [2.5K]3 years ago
4 0

Answer: reactor;fission is the correct answer.

Explanation:

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A Shaolin monk of mass 60 kg is able to do a ‘finger stand’: he supports his whole weight on his two index fingers, giving him a
ss7ja [257]

Answer:

P = 1471500 [Pa]

Explanation:

We must remember that pressure is defined as the relationship between Force over the area.

P=F/A

where:

P = pressure [Pa] (units of pascals)

F = force [N] (units of Newtons)

A = area of contact = 4 [cm²]

But first we must convert from cm² to m²

A = 4[cm^{2}]*\frac{1^{2} m^{2} }{100^{2} cm^{2} }

A = 0.0004 [m²]

Also, the weight should be calculated as follows:

w = m*g

where:

m = mass = 60 [kg]

g = gravity acceleration = 9.81 [m/s²]

Now replacing:

w = 60*9.81\\w = 588.6[N]

And the pressure:

P=588.6/0.0004\\P=1471500 [Pa]

Because 1 [Pa] = 1 [N/m²]

8 0
3 years ago
How long does a player sit out of a game of handball for committing a second or third foul?
yulyashka [42]

Answer:

Walking’ - If a handball player takes more than three steps without dribbling (bouncing the ball) or holds the ball for more than 3 seconds without bouncing it, shooting or passing, then that is deemed ‘walking' and possession is lost.

'Double dribble’ - Handball players cannot receive the ball and bounce it, then hold the ball, and bounce it again. This is termed ‘double dribble’ and is against the rules.

Askmeanything2♡

5 0
3 years ago
A train is pulling four train cars and each car has a mass of 40,000 kg. The train is accelerating at 1.1 m/s^2. What is the for
IgorLugansk [536]

Answer:

176,000 N

Explanation:

Newton's second law:

∑F = ma

F = (4 × 40,000 kg) (1.1 m/s²)

F = 176,000 N

8 0
3 years ago
Read 2 more answers
A proton having an initial velvocity of 20.0i Mm/s enters a uniform magnetic field of magnitude 0.300 T with a direction perpend
Sonja [21]

The time interval for which the proton remains in the field is -

Δt = $\frac{\pi R}{40}.

We have a proton entering a uniform magnetic field which is in a direction perpendicular to the proton's velocity.

We have to determine time interval during which the proton is in the field.

<h3>What is the magnitude of force on the charged particle moving in a uniform magnetic field?</h3>

The magnitude of force on the charged particle moving in a uniform magnetic field is given by -

F = qvB sinθ



According to the question, we have -

Entering Velocity (v) = 20 i  m/s

Magnetic field intensity (B) = 0.3 T

Leaving velocity (u) = - 20 j  m/s

Now -

The entering and leaving velocity vectors have 90 degrees difference between them. Therefore, only a quarter of distance of the complete circular path of radius 'R' is traced by the proton. Therefore -

d = $\frac{2\pi r}{4} = $\frac{\pi R}{2}

Since, the radius of circular path is not given, we will assume it R.

Therefore, time for which proton remained in the field is -

t = $\frac{\pi R}{2v} = \frac{\pi R}{40}

Hence, the time interval for which the proton remains in the field is -

Δt = $\frac{\pi R}{40}

To solve more questions on Force on charged particle, visit the link below-

brainly.com/question/14597200

#SPJ4



 



6 0
1 year ago
Two objects, with different sizes, masses, and temperatures, are placed in thermal contact. in which direction does the energy t
s344n2d4d5 [400]
<span>(c) energy travels from the object at higher temperature
to the object at lower temperature.

Size and mass have no effect.</span>
3 0
3 years ago
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