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3 years ago

The main part of the nuclear power plant is the . Where nuclear reactions take place.

Physics

2 answers:

emmasim [6.3K]3 years ago

7 0

Turbine an unclean fission

chubhunter [2.5K]3 years ago

4 0

Answer: reactor;fission is the correct answer.

Explanation:

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A 20 kg crate initially at rest on a horizontal floor requires a 80 N horizontal force to set it in motion. Find the coefficient

e-lub [12.9K]

Answer:

The coefficient of static friction between the crate and the floor is 0.41

Explanation:

Friction Force

When an object is moving and encounters friction in the air or rough surfaces, it loses acceleration and velocity because the friction force opposes motion.

The friction force when an object is moving on a horizontal surface is calculated by:

$Fr=\mu N$ [1]

Where $\mu$ is the coefficient of static or kinetics friction and N is the normal force.

If no forces other then the weight and the normal are acting upon the y-direction, then the weight and the normal are equal in magnitude:

N = W = m.g

The crate of m=20 Kg has a weight of:

W = 20*9.8

W = 196 N

The normal force is also N=196 N

We can find the coefficient of static friction by solving [1] for $\mu$ :

$\displaystyle \mu=\frac{Fr}{N}$

The friction force is equal to the minimum force required to start moving the object on the floor, thus Fr=80 N and:

$\displaystyle \mu=\frac{80}{196}$

$\mu=0.41$

The coefficient of static friction between the crate and the floor is 0.41

7 0

3 years ago

a 90 kg architect is standing 2 meters from the center of a scaffold help up by a rope on both sides. the scaffold is 6m long an

Mademuasel [1]

We can solve the problem by requiring the equilibrium of the forces and the equilibrium of torques.

1) Equilibrium of forces:
$T_1 - W_p - W_s + T_2 =0$
where
$W_p = (90kg)(9.81 m/s^2)=883 N$ is the weight of the person
$W_s = (200kg)(9.81 m/s^2)=1962 N$ is the weight of the scaffold
Re-arranging, we can write the equation as
$T_1 = 2845 N-T_2$ (1)

2) Equilibrium of torques:
$T_1 \cdot 3 m - W_p \cdot 2 m - T_2 \cdot 3m =0$
where 3 m and 2 m are the distances of the forces from the center of mass of the scaffold.
Using $W_p = 883 N$ and replacing T1 with (1), we find
$2845 N \cdot 3 m - T_2 \cdot 3 m - 833 N \cdot 2 m - T_2 \cdot 3 m=0$
from which we find
$T_2 = 1128 N$

And then, substituting T2 into (1), we find
$T_1 = 1717 N$

8 0

3 years ago

The term test variable refers to:

timofeeve [1]

Answer:

answer should be C.) Independent variable since its the one being changed

Explanation:

4 0

3 years ago

Read 2 more answers

Which is evidence that a convergent boundary once existed

Vladimir79 [104]

Volcanic islands, Mountain ranges

Explanation:

A convergent margin is plate boundary in which plates comes together. There are different types of interactions that occurs around a place where plate converges.

An ocean-continent convergence creates a subduction zone in which the denser oceanic plate sinks beneath the less dense continental crust.
As the oceanic plate begins to subside, it can melt and form chains of volcanic island within the riding continents.
Also, where two plates of equal densities converge, none of them subsides and this leads to upbuilding.
The product can be seen as extensive mountain ranges on earth like the Andes and Himalayas.

Learn more:

Descending lithosphere brainly.com/question/9582362

#learnwithBrainly

8 0

3 years ago

Glycerin (C3H8O3) is a nonvolatile liquid. What is the vapor pressure of a solution made by adding 154 g of glycerin to 316 mL o

garri49 [273]

Answer:

$P_{sol}=50.4\ mm.Hg$