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2 years ago

Please help me solve this

Mathematics

1 answer:

Black_prince [1.1K]2 years ago

5 0

The error is in step 4. The sign was not changed after dividing both sides by -10. Thus, the answer to the inequality should be: -27/10 ≥ x.

<h3>How Negative Number Changes Inequality Sign?</h3>

When we divide or multiply two sides of an inequality by a negative number, the inequality sign is changed to the opposite, i.e. from < to > or from > to <.

In step 4, the sign was not changed after dividing both sides by -10.

The answer should be, -27/10 ≥ x.

Learn more about the inequality on:

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If f(x) = -5-4 and g(x) = -3 -2 find (f-g)(x)

asambeis [7]

<u>Answer:</u>

The correct answer option is D. $-5^x+3x-2$

<u>Step-by-step-explanation:</u>

We are given the following two functions:

$f(x)=-5^x-4$

and

$g(x)= -3x-2$

We are to find $(f-g)(x)$ so we will subtract the function g from function f, arrange the like terms together and combine them like shown below to get:

$(f-g)(x) =(-5^x-4)-(-3x-2)$

$(f-g)(x)=-5^x-4+3x+2$

$(f-g)(x)=-5^x+3x-2$

Therefore, $(f-g)(x)$ is equal to $-5^x+3x-2$ so the correct answer option is D. $-5^x+3x-2$ .

5 0

3 years ago

The length and width of a rectangle are measured as 55 cm and 49 cm, respectively, with an error in measurement of at most 0.1 c

valentina_108 [34]

Answer:

The maximum error in the calculated area of the rectangle is $10.4 \:cm^2$

Step-by-step explanation:

The area of a rectangle with length $L$ and width $W$ is $A= L\cdot W$ so the differential of <em>A</em> is

$dA=\frac{\partial A}{\partial L} \Delta L+\frac{\partial A}{\partial W} \Delta W$

$\frac{\partial A}{\partial L} = W\\\frac{\partial A}{\partial W}=L$ so

$dA=W\Delta L+L \Delta W$

We know that each error is at most 0.1 cm, we have $|\Delta L|\leq 0.1$ , $|\Delta W|\leq 0.1$ . To find the maximum error in the calculated area of the rectangle we take $\Delta L = 0.1$ , $\Delta W = 0.1$ and $L=55$ , $W=49$ . This gives