complete question:
Put these expressions in a small program that will demonstrate whether they are true or false. Paste the code, and output from the program into your submission. Use if statements and output a message indicating that the expression is True or False.
a = 5, b = 4, c = 3, d = 2 ;
(a <= b + 1 )
(a < b && c > b)
(a >= c || d >= 5)
( !(a > b) )
( b >= a && ! (d < b) )
Answer:
a = 5
b = 4
c = 3
d = 2
if a <= b + 1 :
print("True")
else :
print("False")
if a < b and c > b :
print("True")
else :
print("False")
if a >= c or d >= 5:
print("True")
else :
print("False")
if not(a > b):
print("True")
else :
print("False")
if ( b >= a and not(d < b) ):
print("True")
else :
print("False")
Explanation:
I used python to write the code
The equivalent of && in python is and while the equivalent of || is or. The equivalent of ! is not in python .
I wrote an if statement to print True for each expression if it is actually true and the else statement print False if the expression is actually false.
For example the first expression says if a is less than or equal to b + 1(5). This statement is actually true so the expression will print True. a is 5 and b plus 1 is 5, so a is equal to 5 which is true.
if a < b and c > b :
Both expression must be true for the if statement to print True. a is not less than b and c is not greater than b so the expression amount to False.
if a >= c or d >= 5:
One expression must be true for the expression to be True. a >= c is true and d >= 5 is false. So the expression amount to True.
not(a > b)
This simply means negate the statement a > b . This gives False.
( b >= a and not(d < b))
b >= a is false
d < b is true
not(d < b) is false
false and false is definitely False
