1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
snow_lady [41]
2 years ago
10

Pls help i'll give brainlest

Mathematics
2 answers:
Darina [25.2K]2 years ago
7 0

Answer: B. 183 cm^3

V = pi r^2 h/3

V = pi (5^2) (7/3)

V = pi (25) (2.33)

V = 183

kompoz [17]2 years ago
6 0

Answer:

B.183 cm^{3}

Step-by-step explanation:

Volume of cone is V=\pi r^{2} \frac{h}{3}

where h=7 and r=5 (because r=d/2, where d=10)

V=5^{2}\frac{7}{3}\pi

V=25·\frac{7}{3} \pi

V=175/3\pi

V=183.2595715 or 183 cm^{3}

You might be interested in
Which number system BEST describes this set?
LUCKY_DIMON [66]

Answer:

They're all rational numbers.

Integers: A whole number

Natural numbers: positive integers

Rational numbers: Any integer, positive or negative, including fractions

Irrational numbers: number that cannot be written as a ratio of two integers

3 0
3 years ago
Help please? not sure about this
zimovet [89]

9514 1404 393

Answer:

  72 kph

Step-by-step explanation:

The first sentence tells you the speeds are proportional. So, you can write the proportion ...

  kph/mph = 120/75 = x/45

Multiplying by 45 gives x:

  x = (45)(120/75) = 72

72 kph is 45 mph.

8 0
3 years ago
What is the area of the trapezoid with height 10 units? Enter your answer in the box. units2 A rectangle with a length of 5 and
LenaWriter [7]
If by "long leg lengths" you mean the hypotenuse then the area is 116 sq. units.  If you mean the bases of the triangles then the area is 170 sq. units.

If the length of 12 is the hypotenuse, we first must find the base of the triangles using the Pythagorean theorem:

10² + b² = 12²
100 + b² = 144
b² = 44
b = √44 = 6.6

This means we have two triangles and a rectangle.  The area of the rectangle is 5(10) = 50 sq. units.  The area of each triangle is 1/2(6.6)(10) = 33.  Adding all 3 together we have:

50+33+33 = 116 sq. units.

If the 12 is the base, then we have the rectangle with the area of 5(10) = 50 and two triangles each with an area of 1/2(12)(10) = 60:

50+60+60 = 170 sq. units.
3 0
2 years ago
Read 2 more answers
PLS HELP <br>find the unknown side of the triangle below (round to the nearest tenth) <br>​
Nonamiya [84]
22.9 is the closest but not exact. It was probably rounded off.

I used the formula: leg^2+leg^2=hypotenuse^2

(You can use that formula for any right triangle.)
7 0
3 years ago
Keith has 500 in a savings account at the beginning of the summer he wants to have at least 200 at the end of the summer he with
Feliz [49]

Let w be the number of weeks. He withdraws $25 per week, so in w weeks, he withdraws 25w. He starts with $500, so after w weeks he has 500 - 25w. He wants this amount to be at least $200. "At least" means "greater than or equal to."

500 - 25w >= 200

-25w >= -300

w <= 12

Answer: Keith can withdraw $25 per week for at most 12 weeks.

8 0
3 years ago
Read 2 more answers
Other questions:
  • What is the solution to the inequality -4x+3&lt;31
    9·2 answers
  • Graph linear equation -2y=-x+8
    11·1 answer
  • Describe the number 68 in tens and ones
    13·2 answers
  • The moon was about 240,000 miles from earth. What is the distance written as a whole number by a power of ten?
    14·1 answer
  • Solve and graph each inequality please helo this is due tomorrow please 15 points!!​
    5·1 answer
  • $2,000 at 4% for 24 months. Find the interest earned
    15·1 answer
  • 2. Please explain WHY those are the answers
    14·1 answer
  • An airplane flying at an altitude of 12000 feet begins ascending at a rate of 900 per minute. At this rate, how many minutes wil
    10·1 answer
  • Martin is considering the expression 1/2(7x+48)and -(1/2x-3)+4(x+5)​
    10·1 answer
  • Help helphelp helpe hwlp hwlp
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!