Work = force * distance
and newton*meters = Joule
In this case, work = 250N*50m = 12500 J
So the answer is D) 12,500 J
Answer:
6.32 m/s
Explanation:
KE = 1/2 m v^2
sqrt (2 * KE /m) = v = 6.32 m/s
Answer:
Explanation:
initial velocity, u = 8 m/s
vertical height, h = 1 m
θ = 40°
Let the horizontal distance is d and the time taken is t.
Use second equation of motion in vertical direction
h = ut + 1/2 at²
1 = 8 Sin 40 x t + 0.5 x 9.8 t²
1 = 5.14 t - 4.9t²
4.9t² - 5.14 t + 1 = 0
so, t = 0.26 s (smaller value)
So, the horizontal distance is
d = u cos 40 x t
d = 8 cos 40 x 0.26
d = 1.6 m
The kind of vegetation that alfisols support is a temperate forest. Alfisols develop under the temperate broadleaf deciduous forests. Broadleaf trees tend to be nutrient demanding, and their leaves are filled with major nutrient elements. The litter from this type of forest is not the acidic type, either.
1) they are attracting because if you look at the arrows they’re all pointing the same way.
2) if the magnet was turned around they would do the opposite and not attract ( this is called repulsion)
3) magnetic pole
4)magnet
5) magnetic force
6) magnetism
Hope this helps