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Vilka [71]
3 years ago
10

What is the most common source of energy for surface waves

Physics
1 answer:
Elanso [62]3 years ago
5 0

Answer:

The most common source of energy for surface waves is wind. earthquakes. tides. volcanoes.

Explanation:

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What is matter? explain and give example
kotykmax [81]
Matter is generally any physical substance, and it's all around us... a form of matter would be liquid, and water is a liquid.
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3 years ago
The transfer of energy by the movement of particles that are in contact with each other
jeka57 [31]

Answer: I belive that the Answer is C.) Conduction

Explanation:

3 0
3 years ago
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What is the energy (in evev) of a photon of visible light that has a wavelength of 500 nmnm?
lisabon 2012 [21]
<h3>Answer:</h3>
  • E≈2,5 eV
<h3>Explanation:</h3>

_______________

λ=500 nm = 500·10⁻⁹ m

c=3·10⁸ m/s

h=6,63·10⁻³⁴ J·s = 4,14·10⁻¹⁵ eV·s

_______________

E - ?

_______________

\displaystyle \boldsymbol{E}=h\nu =h \frac{c}{\lambda} =4,14\cdot 10^{-15} \; eV\cdot s\cdot \; \frac{3\cdot 10^8\; m/s}{500\cdot 10^{-9}\; m} =2,484\;  eV\approx \boldsymbol{2,5\; eV}

6 0
2 years ago
What happened to a apple's weigh as the plane rose up toward the sky?
uysha [10]

Okay, I don't know if this question is supposed to be a trick question or not. The weight of the apple does not change as the plane travels up the atmosphere, but the MASS changes. Weight doesn't change no matter what environment you're in, but the mass changes in different environments. In this case, the weight is constant but the mass is decreasing as you go higher up.
5 0
3 years ago
In a local bar, a customer slides an empty beer mug down the counter for a refill. The height of the counter is 1.14 m. The mug
defon
Say the horizontal component of the velocity is vx and the vertical is vy.
Initially at t=0 (as the mug leaves the bar) the components are v0x and v0y.
Obviously (I hope!) v0y = 0.

The equations for horizontal and vertical projectile motion (with the positive direction up) are

x = x0 + v0x t
y = y0 + v0y t - 1/2 g t^2 = y0 - 1/2 g t^2

Now choose the origin to be the end of the counter. x0=0 and y0=0. The equations simplify to

x = v0x t
y = - 1/2 g t^2

You know that x = 1.20m when y = -0.88m
From the y equation (and g=10 m/s^2) you can calculate the time that the mug hits the floor.
t = 0.420s
From the x equation we get the initial horizontal velocity
v0x = x/t = 1.2/0.42 = 2.86 m/s

(b) x-component of velocity is constant since there are no horizontal forces so vx = 2.86 m/s
y-component is given by v = u+at with u=0 and a=-g
vy = -gt = -4.2m/s

Now tan(angle) = vy/vx so angle = arctan(vy/vx)
7 0
3 years ago
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