What is the most common source of energy for surface waves

Physics

1 answer:

Elanso [62]3 years ago

5 0

Answer:

The most common source of energy for surface waves is wind. earthquakes. tides. volcanoes.

Explanation:

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0.001225 kg/L x 720 000 000L =?

I am Lyosha [343]

Answer:

0.001225 kg/L × 720 000 000 L = 882000 kg

Explanation:

Given:

The equation to solve is given as:

0.001225 kg/L × 720 000 000 L = ?

Let us write each term of the product in terms of power of 10.

As 0.001225 has 6 digits after the decimal place, therefore, we use the exponent 6 for 10 and the sign is negative. This gives,

$0.001225\ kg/L = 1225\times 10^{-6}\ kg/L$

Now, for 720000000 L there are 6 zeros after 720. So, we use exponent 6 but with a positive sign. This gives,

$720000000\ L=720\times 10^{6}\ L$

Now, finding the product, we get:

$0.001225\ kg/L\times 720000000\ L\\\\=1225\times 10^{-6}\ kg/L\times 720\times 10^6\ L\\\\=(1225\times 720)\times (10^6\times 10^{-6})\ (\frac{kg}{L}\times L)\\\\=882000\times 10^{6-6}\ kg\\\\=882000\times 10^0\ kg\\\\=882000\times 1\ kg\\\\=882000\ kg$

Therefore, the product is equal to:

0.001225 kg/L × 720 000 000 L = 882000 kg

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4 years ago

What is science ? ????????

Arada [10]

Answer:

the intellectual and practical activity encompassing the systematic study of the structure and behaviour of the physical and natural world through observation and experiment.

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3 years ago

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A sound system is being set up in a gazebo in a park. It needs to produce music so that everyone can hear it. How much power wou

Agata [3.3K]

Answer:

Power of the speakers = 1.57 $\times 10^{-6} W$

Explanation:

There are speakers setup in a park and we have to find the power it would require to have intensity of sound to be $10^{-8} W/m^2$ at a distance of 5 meter.

In one dimension the intensity is constant as the wave travels. In two or three dimensions, however, the intensity decreases as you get further from the source.

Intensity is inversely proportional to the square of the distance from the point of sound production.

Here area = 2 $\times \pi \times r^{2}$