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skelet666 [1.2K]
3 years ago
7

The coefficient of performance of a residential heat pump is 1.6. Calculate the heating effect in kJ/s this heat pump will produ

ce when it consumes 4 kW of electrical power.
Physics
1 answer:
Andre45 [30]3 years ago
6 0

Answer:

Q_{H}=6.4kJ/s

Explanation:

Given data

Coefficient of performance of a residential heat pump=1.6

Electrical power P=4kW

Required

Heat Q

Solution

The rate of heat produced is given as

Q_{H}=COP_{HP}Win\\

Substitute the given values

So

Q_{H}=4kW*1.6\\Q_{H}=6.4kJ/s

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Answer:

30N

Explanation:

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What are the parts of a wedge and their function?​
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A wedge is a machine that consists of two inclined planes, giving it a thin end and thick end. A wedge is used to cut or split apart objects. Force is applied to the thick end of the wedge, and the wedge applies force to the object along both of its sloping sides. This force causes the object to split apart

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Pravat exerts a force of 30 N to lift a bag of groceries 0. 5 m. How much work did Pravat do on the bag? Note : Work = Force x D
Black_prince [1.1K]

The amount of work done by Pravat if he exerts a force of 30 N to lift a bag of groceries 0.5m is 15J.

<h3>WORK DONE:</h3>

The work done by a body can be calculated by multiplying the force exerted by the distance moved. That is;

Work done = force (F) × distance (m)

According to this question, Pravat exerts a force of 30N to lift a bag of groceries 0.5 m. The work done is calculated as follows:

Work done = 30N × 0.5m

Work done = 15J

Therefore, the amount of work done by Pravat if he exerts a force of 30 N to lift a bag of groceries 0.5m is 15J.

Learn more about work done at: brainly.com/question/8119756?referrer=searchResults

8 0
2 years ago
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A 20Kg box is pushed across the floor at a constant velocity with a force of 200N. What is the
Shkiper50 [21]

Answer:

The kinetic coefficient of friction between the box and the floor is 1.020.

Explanation:

Let suppose that box is on horizontal ground. According to the Newton's Laws, an object has a net acceleration of zero when either is at rest or moves at constant velocity. Friction is a reaction to the external force that moves the box. Hence, the equation of equilibrium for the 20-Kg box is:

\Sigma F = F-f = 0 (Eq. 1)

Where:

F - External force, measured in newtons.

f - Friction force, measured in newtons.

If we know that F = 200\,N, then the magnitude of the kinetic friction force is:

f = F

f = 200\,N

In addition, friction force is represented by the following formula:

f = \mu_{k}\cdot m\cdot g (Eq. 2)

Where:

\mu_{k} - Kinetic coefficient of friction, dimensionless.

m - Mass, measured in kilograms.

g - Gravitational acceleration, measured in meters per square second.

Now we clear the kinetic coefficient of friction:

\mu_{k} = \frac{f}{m\cdot g}

If we know that f = 200\,N, m = 20\,kg and g = 9.807\,\frac{m}{s^{2}}, then the kinetic coefficient of friction is:

\mu_{k} = \frac{200\,N}{(20\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}

\mu_{k} = 1.020

The kinetic coefficient of friction between the box and the floor is 1.020.

4 0
3 years ago
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