The working equation for this one is:
E = F/Q, where E is the strength of the electric field, F is the electric force and Q is the charge. Substituting the corresponding values, the strength of the electric field is equal to
E = -30 nN/-3 nC
E = 10 nN/nC
The total potential energy associated with the jumper at the end of his fall is 90,000 J.
The given parameters;
- <em>mass of the jumper, m = 51 kg</em>
- <em>height of the bridge. h = 321 m</em>
- <em>spring constant of the cord, k = 32 N/m</em>
- <em>extension of the cord, x = 179 m - 104 m = 75 m</em>
The total potential energy associated with the jumper at the end of his fall is calculated as follows;
U = ¹/₂kx² + mgΔh
where;
<em>Δh is the change in height after falling </em>
U = ¹/₂(32)(75)² + (51)(9.8)(0)
U = 90,000 J
Thus, the total potential energy associated with the jumper at the end of his fall is 90,000 J.
Learn more here:brainly.com/question/15731149
Answer:
560 m
Explanation:
The speed of sound in air is approximately:
v ≈ v₀ + 0.6T
where v₀ is the speed of sound at 0°C (273 K) in m/s, and T is the temperature in Celsius.
The speed of sound at 20°C at that altitude is:
v ≈ 327 + 0.6(20)
v ≈ 339 m/s
The sound travels from the hikers to the mountain and back again, so it travels twice the distance.
339 m/s = 2d / 3.3 s
2d = 1118.7 m
d = 559.35 m
Rounding, the mountain is approximately 560 m away.
Volume = 873 - 50 = 723 cm^3
