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3 years ago

Distinguish between linear momentum and angular momentum.

Physics

1 answer:

Katarina [22]3 years ago

7 0

Linear momentum is in a straight line and depends on the objects mass and velocity.

Angular (rotational) momentum depends on the objects mass, velocity, and radius.

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A 65kg person throws a 0.045kg snowball forward with a ground speed of 30m/s. A second person, with a mass of 60kg, catches the

asambeis [7]

Answer:

v₁ = 2.48m/s, v₂ = 0.02m/s

Explanation:

Momentum p must be conserved. p = mv

1) First person throwing the snow ball. The momentum before the throw:

p = (65kg + 0.045kg) * 2.5 m/s

The momentum after the throw:

p = 65kg * v₁ + 0.045kg * 30m/s

Solving for the velocity v₁ of person 1:

v₁ = ((65kg + 0.045kg) * 2.5 m/s - 0.045kg * 30m/s) / 65kg = 2.48m/s

2) Second person catching the ball. The momentum before the catch:

p = 0.045kg * 30m/s + 60kg * 0m/s

The momentum after the catch:

p = (60kg + 0.045kg) * v₂

Solving for velocity v₂ of person 2:

v₂ = 0.045kg * 30m/s / (60kg + 0.045kg) = 0.02 m/s

5 0

3 years ago

Which of the following is considered to be a vector?

AVprozaik [17]

Answer: B) Velocity

Explanation:

Velocity is a vector quantity. Velocities have both magnitude and direction.

8 0

2 years ago

Read 2 more answers

It takes 25N or force to drag a box along the floor at a constant speed. If the coefficient of friction is .3, what is the mass

Nataliya [291]

The mass of the box is 8.5 kg.

Mass can be defined as the quantity of matter contained in a body.

To calculate the mass of the box, we use the formula

Formula:

F = mgμ............. Equation 1

Where:

F = Force
m = mass of the box
g = acceleration due to gravity
μ = coefficient of friction

Make m the subject of the equation

m = F/gμ..................... Equation 2

From the question,

Given:

F = 25 N
g = 9.8 m/s²
μ = 0.3

Substitute these values into equation 2

m = 25/(0.3×9.8)
m = 25/2.94
m = 8.5 kg

Hence, the mass of the box is 8.5 kg.

Learn more about mass here: brainly.com/question/26150306

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6 0

1 year ago

A hammer taps on the end of a 3.4-m-long metal bar at room temperature. A microphone at the other end of the bar picks up two pu

OLEGan [10]

Answer:

S = 2266.67 m/s

Explanation:

Given,

length of the metal = 3.4 m

pulses are separated in time = 8.4 ms

speed of sound in air= 343 m/s

speed of sound in this metal = ?

time taken

$t = \dfrac{distance}{speed}$

$t = \dfrac{3.4}{343}$

t = 9.9 ms

speed of sound in the metal is fast

t = 9.9 - 8.4 = 1.5 ms

time for which sound is in metal is equal to 1.5 ms

speed of sound in metal

$speed= \dfrac{distance}{time}$

$S = \dfrac{3.4}{1.5 \times 10^{-3}}$

S = 2266.67 m/s

Speed of sound in metal is equal to S = 2266.67 m/s

7 0

3 years ago

A car with a mass of 1,500 kg accelerates at a rate of 3.0

adoni [48]

Answer:

4500 N

Explanation:

F = ma

= 1500 kg * 3 m/s^2 = 4500 N

edited to correct units !

7 0

2 years ago