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Ira Lisetskai [31]
2 years ago
6

Classify each of the following substances as a compound or element.

Chemistry
1 answer:
baherus [9]2 years ago
4 0

Answer:

A. Element

B. Compound

C. Compound

D. Element

E. Compound

F. Compound

Explanation:

Elements are what is already on the periodic table and compounds are the substances created when they are combined.

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c) If a mixture of zinc powder and cobalt(II) oxide is heated, the following reaction occurs: Zn(s) + COO(s) → ZnO(s) + Co(s) (i
bazaltina [42]

Answer:

The metal which reduces the other compound is the one higher in reactivity. So in this case, it is.

Explanation:

5 0
2 years ago
Help me with 4,5 plz
Helen [10]
The answer to 4 is A.                                              
The answer to 5 is C.
7 0
3 years ago
Which notation represents atoms that have the same number of protons but a different neutron?
ArbitrLikvidat [17]
Those are called isotopes,

the answer is 3.

each element has its own unique number of protons (atomic number) but a different number of neutrons can be shown in example number 3.
5 0
3 years ago
What particle joins or bonds atoms to form a compound or molecule
agasfer [191]

<h3>I hope it is helpful for you ....</h3>

6 0
3 years ago
For the reaction A + B + C → D + E, the initial reaction rate was measured for various initial concentrations of reactants. The
babymother [125]

Answer : The order of reaction with respect to A is, second order reaction.

The order of reaction with respect to B is, zero order reaction.

The order of reaction with respect to C is, first order reaction.

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

A+B+C\rightarrow D+E

Rate law expression for the reaction:

\text{Rate}=k[A]^a[B]^b[C]^c

where,

a = order with respect to A

b = order with respect to B

c = order with respect to C

Expression for rate law for first observation:

6.0\times 10^{-4}=k(0.20)^a(0.20)^b(0.20)^c ....(1)

Expression for rate law for second observation:

1.8\times 10^{-3}=k(0.20)^a(0.20)^b(0.60)^c ....(2)

Expression for rate law for third observation:

2.4\times 10^{-3}=k(0.40)^a(0.20)^b(0.20)^c ....(3)

Expression for rate law for fourth observation:

2.4\times 10^{-3}=k(0.40)^a(0.40)^b(0.20)^c ....(4)

Dividing 1 from 2, we get:

\frac{1.8\times 10^{-3}}{6.0\times 10^{-4}}=\frac{k(0.20)^a(0.20)^b(0.60)^c}{k(0.20)^a(0.20)^b(0.20)^c}\\\\3=3^c\\c=1

Dividing 1 from 3, we get:

\frac{2.4\times 10^{-3}}{6.0\times 10^{-4}}=\frac{k(0.40)^a(0.20)^b(0.20)^c}{k(0.20)^a(0.20)^b(0.20)^c}\\\\4=2^a\\a=2

Dividing 3 from 4, we get:

\frac{2.4\times 10^{-3}}{2.4\times 10^{-3}}=\frac{k(0.40)^a(0.40)^b(0.20)^c}{k(0.40)^a(0.20)^b(0.20)^c}\\\\1=2^b\\b=0

Thus, the rate law becomes:

\text{Rate}=k[A]^2[B]^0[C]^1

Thus,

The order of reaction with respect to A is, second order reaction.

The order of reaction with respect to B is, zero order reaction.

The order of reaction with respect to C is, first order reaction.

5 0
3 years ago
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