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sertanlavr [38]
3 years ago
5

What is the correct IUPAC name for NH4CL?

Chemistry
2 answers:
blondinia [14]3 years ago
6 0
What is the correct IUPAC name for NH4CL? Ammonium chlorid
Andrews [41]3 years ago
3 0
Ammonium chloride is the correct name for NH4CL
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A balloon contains helium gas expands from 230ml to 860 ml as more helium is added. What was the initial quantity of helium pres
Kisachek [45]

Answer:

n₁ = 1.0× 10⁻⁴ mol

Explanation:

Given data:

Initial volume of balloon = 230 mL

Initial number of moles of He =?

Final number of moles of He = 3.8 × 10⁻⁴ mol

Final volume of balloon = 860 mL

Solution:

The given problem will be solve through Avogadro law,

"Number of moles of gas and volume are directly proportional to each other at constant temperature and constant pressure"

Mathematical relationship:

V₁/n₁ = V₂/n₂

No we will put the values.

230 mL  /n₁   = 860 mL/ 3.8 × 10⁻⁴ mol

n₁ = 230 mL× 3.8 × 10⁻⁴ mol/ 860 mL

n₁ = 874 × 10⁻⁴ mol. mL / 860 mL

n₁ = 1.0× 10⁻⁴ mol

6 0
3 years ago
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Sammy and Marisa are asked to determine what kind of bonds are present in the
kotykmax [81]

Answer:

I think Sammy is right because I'm sure the compound contains ionic bonds

7 0
2 years ago
-You wish to make a 0.203 M hydrochloric acid solution from a stock solution of 6.00 M hydrochloric acid. How much concentrated
lubasha [3.4K]

For all three questions, we will use the fact that

  • molarity = (moles of solute)/(liters of solution)

1) For 175 mL of solution at 0.203 M, this means that:

  • 0.203 = (moles of solute)/0.175
  • moles of solute = 0.035523 mol

Considering the hydrochloric acid solution, if we have 0.035523 mol, then:

  • 6.00 = 0.035523/(liters of solution)
  • liters of solution = 0.035523/6.00 = 0.0059205 = <u>5.92 mL (to 3 sf)</u>

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2) If there is 20.3 mL = 0.0203 L, then:

  • 8.20 = (moles of solute)/0.0203
  • moles of solute = 0.16646 mol

This means that the molarity of the diluted solution is:

  • 0.16646/(0.200) = <u>0.832 M (to 3 sf)</u>

<u />

3) If we need 1.50 L of 0.700 M solution, then:

  • 0.700 = (moles of solute)/1.50
  • moles of solute = 1.05 mol

Considering the 9.36 M acid solution, from which we need 1.05 mol of perchloric acid from,

  • 9.36 = 1.05/(liters of solution)
  • liters of solution = 1.05/9.36, which is 0.11217948717949 L, or <u>112 mL (to 3 sf)</u>
8 0
1 year ago
Consider the pka (3.75) of formic acid, h-cooh as a reference. with appropriate examples, show how inductive, dipole, and resona
Luden [163]
Formic acid is the simplest carboxylic acid with a structure of HCOOH and has a pka of 3.75. The pka refers to the acidity of the molecule, which in this example refers to the molecules ability to give up the proton of the O-H. A decrease in the pka value corresponds to an increase in acidity, or an increase in the ability to give up a proton. When an acid gives up a proton, the remaining anionic species (in this case HCOO-) is called the conjugate base, and an increase in the stability of the conjugate base corresponds to an increase in acidity.

The pka of a carboxylic can be affected greatly by the presence of various functional groups within its structure. An example of an inductive effect changing the pka can be shown with trichloroacetic acid, Cl3CCOOH. This molecule has a pka of 0.7. The decrease in pka relative to formic acid is due to the presence of the Cl3C- group, and more specifically the presence of the chlorine atoms. The electronegative chlorine atoms are able to withdraw the electron density away from the oxygen atoms and towards themselves, thus helping to stabilize the negative charge and stabilize the conjugate base. This results in an increase in acidity and decrease in pka.

The same Cl3CCOOH example can be used to explain how dipoles can effect the acidity of carboxylic acids. Compared to standard acetic acid, H3CCOOH with a pka of 4.76, trichloroacetic acid is much more acidic. The difference between these structures is the presence of C-Cl bonds in place of C-H bonds. A C-Cl bond is much more polar than a C-H bond, due the large electronegativity of the chlorine atom. This results in a carbon with a partial positive charge and a chlorine with a partial negative charge. In the conjugate base of the acid, where the molecule has a negative charge localized on the oxygen atoms, the dipole moment of the C-Cl bond is oriented such that the partial positive charge is on the carbon that is adjacent to the oxygen atoms containing the negative charge. Therefore, the electrostatic attraction between the positive end of the C-Cl dipole and the negative charge of the anionic oxygen helps to stabilize the entire species. This level of stabilization is not present in acetic acid where there are C-H bonds instead of C-Cl bonds since the C-H bonds do not have a large dipole moment.

To understand how resonance can affect the pka of a species, we can simply compare the pka of a simple alcohol such as methanol, CH3OH, and formic acid, HCOOH. The pka of methanol is 16, suggesting that is is a very weak acid. Once methanol gives up that proton to become the conjugate base CH3O-, the charge cannot be stabilized in any way and is simply localized on the oxygen atom. However, with a carboxylic acid, the conjugate base, HCOO-, can stabilize the negative charge. The lone pair electrons containing the charge on the oxygen atom are able to migrate to the other oxygen atom of the carboxylic acid. The negative charge can now be shared between the two electronegative oxygen atoms, thus stabilizing the charge and decreasing the pka.
3 0
3 years ago
In a mixture of carbon dioxide in water ( a soft drink ) the Carbon Dioxide is the solute
Nataly [62]

Answer:

true :)

Explanation:

hope this helps :)

4 0
3 years ago
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