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umka2103 [35]
3 years ago
6

The sum of these consecutive integers is equal to 9 less than 4 times the least of the integer. Find the three integers

Mathematics
1 answer:
Ainat [17]3 years ago
4 0

Answer:


Step-by-step explanation:

X+x+1+x+2=4x-9

3x+3=4x-9

X=12

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A: -50<br><br> B: -5<br><br> C: 2<br><br> D: 8
fiasKO [112]

Answer and explanation:

<u>You're trying to figure out the value of x</u>

<em>If g(x) = 14 then that means that 4x + 6 = 14</em>

4x + 6 = 14  <em>Solve for x</em>

    - 6   - 6   <em>Subtract 6 from both sides to get 4x alone</em>

4x = 8         <em> Divide 4x by 4 and 8 by 4</em>

x = 2

<u>Plug in 2 to see if it properly works</u>

<em>g(2) must equal 14</em>

g(2) = 4(2) + 6

g(2) = 8 + 6

g(2) = 14

The answer would be C: 2

8 0
3 years ago
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ruslelena [56]

Answe65

Step-by-step explanationthat the anews

3 0
2 years ago
Do the equations 5y−2x=18 and 6x=−4y−10 form a system of linear equations?
Oduvanchick [21]
  • Yes, The equations 5y−2x=18 and 6x = −4y−10 form a system of linear equations.

For clear understanding refer to the attachment please! :)

5 0
2 years ago
1. A teacher had 8 packages of paper she wanted to split equally into 3 piles. How much should be in each pile? Between what two
castortr0y [4]

Answer:

If division of the packages in fractional numbers was possible, it should be 2.667 packages per pile.

The answer lies between 2 and 3 packages per pile.

Step-by-step explanation:

This can be solved as a simple division.

To split 8 packages in 3, this should correspond to 8/3≈2.667.

If division of the packages in fractional numbers was possible, it should be 2.667 packages per pile.

Other way to think about it is like mentally allocating a package in each pile. We can go up to 2 packages per pile (a total of 6 packages), and we can only add a package to 2 piles, letting the last pile to have only two packages.

Then, we have 2 piles with 3 packages and one pile with 2 packages.

4 0
3 years ago
88÷6080 use campatible numbers to find two estimates
Shalnov [3]
69 idk if I got this right
4 0
3 years ago
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