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2 years ago

PLEASE HELP ASAP!!!!!!!!!!!!

Chemistry

1 answer:

Aleks04 [339]2 years ago

7 0

In the scientific sense the two examples of people doing work is: A and D

<h3>Meaning of Work </h3>

Work can be defined as a result of applying force to a particular object that changes its displacement in the direction of the applied force.

Work can only be done when their is a force that is being applied and a displacement that occurs.

In conclusion, In the scientific sense the two examples of people doing work is: A and D

Lear more about Work: brainly.com/question/25573309

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Which of the following describes the arrangement of valence electrons in a bond between H and F?

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You weigh out 0.1183 g of a complex salt to analyze for the percentage of cyanide ion in your complex salt. After dissolving the

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Answer:

25.35%

Explanation:

Again let me restate the the equation of the reaction;

H2O (ℓ) + 2 MnO4 - (aq) + 3 CN- (aq) → 2 MnO2 (s) + 3 CNO- (aq) + 2 OH- (aq)

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8.1957 * 10^-4 moles of MnO4 - reacts with 8.1957 * 10^-4 * 3/2

= 1.229 * 10^-3 moles of CN-

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3 years ago

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3 years ago

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zhuklara [117]

Answer:

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Explanation:

Solubility equilibrium of $Zn(CH_{3}COO)_{2}$ :

$Zn(CH_{3}COO)_{2}\rightleftharpoons Zn^{2+}+2CH_{3}COO^{-}$

Solubility product of $Zn(CH_{3}COO)_{2}$ ( $K_{sp}$ ) is written as- $K_{sp}=[Zn^{2+}][CH_{3}COO^{-}]^{2}$

Where $[Zn^{2+}]$ and $[CH_{3}COO^{-}]$ represents equilibrium concentration (in molarity) of $Zn^{2+}$ and $CH_{3}COO^{-}$ respectively.

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So, solubility of $Zn(CH_{3}COO)_{2}$ = $\frac{43.0}{183.48}M$ = 0.234M

1 mol of $Zn(CH_{3}COO)_{2}$ gives 1 mol of $Zn^{2+}$ and 2 moles of $CH_{3}COO^{-}$ upon dissociation.

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8 0

3 years ago