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3 years ago

Why does hybridization of orbitals occur?

1 answer:

5 0

Hybridization of orbitals is the concept of incorporation atomic orbitals into new hybrid orbitals appropriate for the pairing of electrons to form chemical bonds in valence bond theory.

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The arrows shown in the asthenosphere represent the inferred

nata0808 [166]

Red arrows represent the movement of the mantle due to convection. Black arrows represent the movement of the plates due to gravity. Scientists think that this transfer of thermal energy from core to mantle causes convection in the mantle.

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3 years ago

If atoms are not destroyed, what happens to them

Snowcat [4.5K]

The 1st law of thermodynamics doesn't specify that matter can be created nor destroyed, but that the total amount of energy in a closed system cannot be created nor destroyed though it can be changed from one form to another.

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4 years ago

How do atoms explain the pattern that the mass of the products always equals the mass of the reaction?

galina1969 [7]

The law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products. ... Because atoms are only rearranged in a chemical reaction, there must be the same number of sodium atoms and chlorine atoms in both the reactants and products.

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3 years ago

Just as the depletion of stratospheric ozone today threatens life on Earth today, its accumulation was one of the crucial proces

inessss [21]

Answer:

(a) rate = -(1/3) Δ[O₂]/Δt = +(1/2) Δ[O₃]/Δt

(b) Δ[O₃]/Δt = 1.07x10⁻⁵ mol/Ls

Explanation:

By definition, t<u>he reaction rate for a chemical reaction can be expressed by the decrease in the concentration of reactants or the increase in the concentration of products:</u>

aX → bY (1)

$rate= -\frac{1}{a} \frac{\Delta[X]}{ \Delta t} = +\frac{1}{b} \frac{\Delta[Y]}{ \Delta t}$

<em>where, a and b are the coefficients of de reactant X and product Y, respectively. </em>

(a) Based on the definition above, we can express the rate of reaction (2) as follows:

3O₂(g) → 2O₃(g) (2)

$rate = -\frac{1}{3} \frac{\Delta[O_{2}]}{\Delta t} = +\frac{1}{2} \frac{ \Delta[O_{3}]}{ \Delta t}$ (3)

(b) From the rate of disappearance of O₂ in equation (3), we can find the rate of appearance of O₃:

$rate = +\frac{1}{2} \frac{\Delta[O_{3}]}{ \Delta t} = -\frac{1}{3} \frac{\Delta[O_{2}]}{ \Delta t}$

$+\frac{\Delta[O_{3}]}{ \Delta t} = -\frac{2}{3} \frac{\Delta[-1.61 \cdot 10^{-5}]}{ \Delta t}$

$\frac{\Delta[O_{3}]}{ \Delta t} = 1.07 \cdot 10^{-5} \frac{mol}{Ls}$

So the rate of appearance of O₃ is 1.07x10⁻⁵ mol/Ls.

Have a nice day!

6 0

4 years ago

What is a tremor? how does occur?

Klio2033 [76]

Explanation:

$\sf \: A \: tremor \: is \: a \: rhythmic \: shaking\: movement \: in \: one \\ \sf or \: more \: parts \: of \: your \: body. \\ \sf It \: is \: involuntary, \: meaning \: that \: you \: cannot \\ \sf control\: it. \: This \: shaking \: happens \\ \sf because \: of \: muscle \: contractions. \\\sf A \: tremor \: is \: most \: often \: in \: your \: hands, \\ \sf but \: it \: could \: also \: affect \: your \: arms, \\ \sf head, \: vocal cords, \: trunk, \: and \: legs.$

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3 years ago