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Andre45 [30]
1 year ago
9

Calculate the mass of pure sodium chloride will yield enough hydrogen chloride gas to tralize 25 cm² of 0.5 M potassium trioxo-

bonate(IV) solution. NACI=58.5, HC1 = 36.5, K,CO, = 138)​
Chemistry
1 answer:
Serggg [28]1 year ago
6 0
It equals k, Co =138
You might be interested in
Help pls!!!!!!!!!!!!!​
UkoKoshka [18]

Answer:

1.   C + O₂ → CO₂

2.  C + CO₂ → 2 CO

3. Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂

4 0
2 years ago
A 800N mountain climber scales a 160m cliff. How much work is done by the mountain climber?
Fittoniya [83]

Answer:

Work done, W = 128 kJ

Explanation:

Given that,

Weight of a mountain climber, F = 800 N

It climbs to a cliff that is 160 m high.

We need to find the work done by the mountain climber. The work done by an object is given by the formula as follows :

W = Fd

Put the values of F and d.

W = 800 N × 160 m

W = 128000 J

or

W = 128 kJ

So, 128 kJ of work is done by the mountain climber.

3 0
2 years ago
The decomposition of N2O to N2 and O2 is a first-order reaction. At 730°C, the rate constant of the reaction is 1.94 × 10-4 min-
grin007 [14]

Answer:

Total pressure 5.875 atm

Explanation:

The equation for above decomposition is

2N_2O \rightarrow 2N_2 + O_2

rate constant k =  1.94\times 10^{-4} min^{-1}

Half life t_{1/2} = \frac{0.693}{k} = 3572 min

Initial pressure N_2 O = 4.70 atm

Pressure after 3572 min = P

According to first order kinematics

k = \frac{1}{t} ln\frac{4.70}{P}

1.94\times 10^{-4} = \frac{1}{3572} \frac{4.70}{P}

solving for P we get

P = 2.35 atm

2N_2O \rightarrow 2N_2 + O_2

initial           4.70                         0             0

change        -2x                          +2x           +x

final             4.70 -2x                     2x           x

pressure ofO_2 after first half life  = 2.35 = 4.70 - 2x

                                                          x = 1.175

pressure of N_2 after first half life  =  2x = 2(1.175) = 2.35 ATM

Total pressure  = 2.35 + 2.35 + 1.175

                          = 5.875 atm

5 0
3 years ago
Read 2 more answers
What is the isotope notation for an ion of silver-109 with a charge of positive 1
Arisa [49]

Answer:

The isotope notation for an ion of silver-109 with a charge of positive 1 is _{47}^{109}Ag^{1+}.

Explanation:

The elements with same atomic number with different mass numbers are called isotopes.

The isotopes of silver is as follows.

_{47}^{109}Ag,_{47}^{107}Ag

From the above two isotopes have same atomic number and different mass number.

From the given,the isotope notation for an ion of silver-109 with a charge of positive 1

It can be represented is as follows.

_{47}^{109}Ag^{1+}

General representation of isotope is as in attachment.

6 0
3 years ago
Which event would be impossible to explain by using John Dalton’s model of the atom?
Dvinal [7]
<span>Dalton's atomic theory proposed that all matter was composed of atoms, indivisible and indestructible building blocks. While all atoms of an element were identical, different elements had atoms of differing size and mass. Dalton also stated that all compounds were composed of combinations of these atoms in defined ratios. He postulated that chemical reactions resulted in the rearrangement of the reacting atom.



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6 0
2 years ago
Read 2 more answers
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