B----------- oxide is the correct answer
Answer:
The pressure increases to 3.5 atm.
Solution:
According to Gay-Lussac's Law, " At constant volume and mass the pressure of gas is directly proportional to the applied temperature".
For initial and final states of a gas the equation is,
P₁ / T₁ = P₂ / T₂
Solving for P₂,
P₂ = P₁ T₂ / T₁ ----- (1)
Data Given;
P₁ = 3 atm
T₁ = 27 °C + 273 = 300 K
T₂ = 77 °C + 273 = 350 K
Putting values in eq. 1,
P₂ = (3 atm × 350 K) ÷ 300 K
P₂ = 3.5 atm
Answer:
9.8×10^-4...... is the answer
<h3>
Answer:</h3>
5.6 Liters
<h3>
Explanation:</h3>
- N.T.P. refers to the standard temperature and pressure (S.T.P).
We need to know that;
- One mole of a gas occupies a volume of 22.4 liters at N.T.P.
In this case;
We have 11 g of CO₂
But, 1 mole of CO₂ occupies 22.4 l at N.T.P.
1 mole of CO₂ = 44 g
Therefore;
44 g of CO₂ = 22.4 liters
What about 11 g ?
= (11 g × 22.4 l)÷ 44 g
= 5.6 l
Therefore, 11 g of CO₂ will occupy a volume of 5.6 liters at N.T.P.
