1s(2)2s(2)2p(6)3s(2)3p(6)4s(2)3d(6)
Answer:
H₂SO₄ (aq) + H₂O (l) → HSO₄⁻ (aq) + H₃O⁺ (aq)
HSO₄⁻ (aq) + H₂O (l) ⇄ SO₄⁻²(aq) + H₃O⁺ (aq) Ka
Explanation:
The sulfuric acid is a dyprotic acid.
It is a considered a strong acid but only the first deprotonation is strong.
Second deprotonation is totally weak
That's why we have equilibrium when it release the second proton.
Since a deprotonation is treated for a weak acid, the acid is considered not to completely dissociate, that's why the equilibrium
Answer:
Anion
Explanation:
Anion is an atom or group of atoms that are negatively charged.
Cations are positively charged
Anode is a positively charged pole that conducts electricity (remember electrolysis)
Cathode is a negatively charged pole that conducts electricity (remember electrolysis too)
Answer:
Explanation:
<u>1) Data:</u>
a) [OH⁻] = 2.1 × 10⁻⁶ M . . . (the symbol g shown in the question is a typo)
b) pH = ?
<u>2) Formulae:</u>
<u>3) Solution:</u>
- pOH = log ( 1 / 2.1 × 10⁻⁶ ) = 5.7
- pH = 14 - pOH = 14 - 5.7 = 8.3