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3 years ago

11

Theresa invested $5,000 in an account she expects will earn 7% annually. Approximately how many years will it take for the accou

nt to double in value?

1 answer:

Lady_Fox [76]3 years ago

3 0

About 7-8 years More. The real answer would be 7.14285714286

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Which of the following statements is NOT true about neutralization?

rjkz [21]

Answer:

D

Explanation:

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3 years ago

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Balance these chem problems

nikklg [1K]

These are hard sorry

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3 years ago

Phosphorus p4 burns in oxygen to form diphosphorus pentoxide what is the balanced chemical equation representing this chemical r

ahrayia [7]

Answer:

P₄ + 5O₂ → 2P₂O₅

Explanation:

Phosphorus burn in the presence of air and produced diphosphorus pentoxide.

Chemical equation:

P₄ + O₂ → P₂O₅

Balanced chemical equation:

P₄ + 5O₂ → 2P₂O₅

Equation is balanced because there are four phosphorus atoms ans ten oxygen atoms in both side of equation.

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P₂O₅ 2

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3 years ago

Write the reaction equation and equilibrium equation for dopamine

elena-s [515]

Answer:

The see explanation

Explanation:

In this case, we have an <u>"amine"</u> group in the dopamine structure. So, the dopamine will act as a <u>"base"</u>. A base is a substance that has the ability to <u>accept hydrogens</u>, therefore, the $NH_2$ will take hydrogen from the water molecule. Additionally, the water will produce the $OH^-$ ion and the $NH_2$ will be converted into $NH^+_3$ .

See figure 1

I hope it helps!

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3 years ago

To aid in the prevention of tooth decay, it is recommended that drinking water contains 0.900 ppm fluoride (F-). A) How many g o

Romashka-Z-Leto [24]

Answer:

a) <u>1.740 g</u> of F- must be added to a cylindrical water reservoir

b) Grams of sodium fluoride, NaF, that contain this much fluoride:

3.84 g

Explanation:

Step 1. calculate the volume of the tank:

Volume of cylinder =

$\pi r^{2}h$ ,

Here r = radius of the cylinder = d/2

h = depth = 21.80m

$r=\frac{d}{2}$

$=\frac{3.36x10^{2}}{2}$

= 168 m

Volume =

$=\frac{22\times 168^{2}\times 21.80}{7}$

$=1.93\times 10^{6} m^{3}$

2.Convert ppm to g/m3 and Solve for mass of F-

$1ppm = 1g/m^{3}$

$0.9ppm = 0.9g/m^{3}$

Because both ppm and g/m3 are same quantity .

$g/m^{3} =\frac{mass\ of\ F-(g)}{Volume\ m^{3}}\times 10^{6}$

$0.9 =\frac{mass\ of\ F-}{1.93\times 10^{6} m^{3}}\times 10^{6}$

$mass\ of\ F- =1.740g$

mass of F- required = 1.740 g

3. Apply <u>mole concept </u>to calculate grams of sodium fluoride produced

mass of 1 mole of F2 = 38 g

mass of 1 mole of NaF = 42 g

(from periodic table calculate molar mass)

$2Na+F_{2}\rightarrow 2NaF$

Here 1 mole of F2 produce = 2 mole of NaF

So,

38 g of F2 produce = 2 x 42 g of NaF

38 g of F2 produce = 84 g of NaF

1 g of F2 produce = 84/38 g of NaF

1.74 g F2 produce =

$\frac {84}{38}\times 1.74$

1.74 g F2 produce = 3.84 g of NaF

3.84 g of NaF is produced

3 0

3 years ago