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Dennis_Churaev [7]
3 years ago
15

Work out the percentage change to 2 decimal places when a price of £78.98 is increased to £100

Mathematics
1 answer:
Levart [38]3 years ago
4 0

Answer:

The percentage is 26.6%

Step-by-step explanation:

Here, we want to

work

out the percentage change

To do this, we use the percentage change formula

This is,

percentage change = new value-old value)/old value * 100%

= (100-78.98)/78.98 * 100%

21.02/78.98 * 100% = 26.6%

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Step-by-step explanation:

and they should give you the answer

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2 years ago
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If z^2+1/z^2=11 , find the value of z^3-1/z^3,using only the positive value of z-1/z
vredina [299]
Hello,

Let's assume

t=z- \dfrac{1}{z} \\\\

t^2=z^2-2+ \dfrac{1}{z^2}= 11-2=9==\ \textgreater \ t=3\\\\

t^3=z^3-3z^2* \dfrac{1}{z} +3z* \dfrac{1}{z^2} - \dfrac{1}{z^3} \\\\
=z^3 - \dfrac{1}{z^3} -3(z-\dfrac{1}{z})\\\\
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7 0
3 years ago
The table below shows pairs of value that satisfy a linear function.
neonofarm [45]

Answer:

-27

Step-by-step explanation:

4 0
3 years ago
Mrs Dang drove her daughter to school at the average speed of 45 miles per hour. She returned home by the same route at the aver
drek231 [11]

Answer: Time it took her to get to the school is 0.6 hours

The distance of the school from their home is 27 miles

Step-by-step explanation:

Mrs Dang drove her daughter to school at the average speed of 45 miles per hour.

Let x miles = distance from the school to their home.

Distance = speed × time

Time = distance / speed

Time used in going to school will be

x/45

She returned home by the same route. This means that distance back home is also x miles.

She returned at an average speed of 30 miles per hour.

Time used in returning home from school will be x/30

x/45

If the trip took one half hour, then the time spent in going to school and the time spent in returning is 1 1/2 hours = 1.5 hours. Therefore

x/30 + x/45 = 1.5

(15x + 10x) /450 = 1.5

15x + 10x = 450 × 1.5 = 675

25x = 675

x = 675/25 = 27

Time it took her to get to the school will be x/45

= 27/45 = 0.6 hours

8 0
3 years ago
Last year, Susan had 10,000 to invest. She invested some of it in an account that paid 6%
katrin2010 [14]

Answer:

In the account that paid 6% Susan invest \$6,000

In the account that paid 5% Susan invest \$4,000

Step-by-step explanation:

we know that

The simple interest formula is equal to

I=P(rt)

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

Part a) account that paid 6% simple interest per year

in this problem we have

t=1\ years\\ P=\$x\\r=0.06

substitute in the formula above

I1=x(0.06*1)

I1=0.06x

Part b) account that paid 5% simple interest per year

in this problem we have

t=1\ years\\ P=\$10,000-\$x\\r=0.05

substitute in the formula above

I2=(10,000-x)(0.05*1)

I2=500-0.05x

we know that

I1+I2=\$560

substitute and solve for x

0.06x+500-0.05x=560

0.01x=560-500

0.01x=60

x=\$6.000

therefore

In the account that paid 6% Susan invest \$6,000

In the account that paid 5% Susan invest \$4,000

6 0
3 years ago
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