Answer:
The cell interior would experience higher than normal Na+ concentrations and lower than normal K+ concentrations.
Explanation:
Na+/K+ ATPase exists in two forms: Its phosphorylated form has a high affinity for K+ and low affinity for Na+. ATP hydrolysis and phosphorylation of the Na+/K+ pump favor the release of Na+ outside the cell and binding of K+ ions from the outside of the cell. Dephosphorylation of the pump increases its affinity for Na+ and reduces that for K+ ions resulting in the release of K+ ions inside the cells and binding to the Na+ from the cells.
The presence of ATP analog would not allow the pump to obtain its phosphorylated form. Therefore, Na+ ions would not be released outside the cells. This would increase the Na+ concentration inside the cell above the normal. Similarly, the pump would not be able to pick the K+ from the outside of the cell resulting in reduced cellular K+ concentration below the normal range.
0.388 Hope this helped let me know if it was wrong :)
Answer:
Both of them have developed tissue system. Both of their cell are Eukaryote Mitochondria and other cell organisms are found in both
<span> water is a solvent. It helps to break waste and nutrients down in the </span>cell so <span>that they can be moved through the various membranes. this is necessary in a cell </span><span />
Answer and Explanation:
The cell was placed in a hypertonic solution. Glucose is a monosaccharide while starch is a polysaccharide. The concentration on the outside is higher compared to that on the inside. The cells have cell membrane that is semi-permeable.
Movement of molecules is dependent on the concentation gradient. However, the size of molecules determine the diffusion rate. Small and light molecules diffuse faster than large and heavy molecules thus glucose diffused faster than starch.
The cell membrane being permeable suggested that it allows molecules of small sizes to pass but not large ones.
