Whenever a vehicle is in motion, it has got kinetic energy. Kinetic energy has a direct relationship with the stopping distance. Kinetic energy is dependent on the mass of the vehicle and also the velocity at which it is traveling. In case of a small vehicle, the mass of the vehicle will be small and so the stopping distance will also be less compared to a large vehicle. In the case of the large vehicle traveling at the same velocity as the small vehicle, the stopping distance will be greater because the large vehicle has a larger mass. So in case of a small vehicle the kinetic energy will be less and so the distance for stopping will be less than that of the large vehicle.
m₁ = mass of the first object = 3.0 kg
m₂ = mass of the second object = 3.0 kg
r = distance between the first and second object = 1.0 m
G = universal gravitational constant = 6.67 x 10⁻¹¹ N m²/kg²
F = force of gravity between the two objects = ?
according to law of gravitation, force of attraction "F" between two objects m₁ and m₂, placed distance "r" apart is given as
F = G m₁ m₂/r²
inserting the values
F = (6.67 x 10⁻¹¹) (3.0) (3.0)/(1.0)²
F = (6.67 x 10⁻¹¹) (9.0)
F = 60.03 x 10⁻¹¹ N
F = 6.003 x 10⁻¹⁰ N
260 meters im pretty sure because rate*time=distance
Answer:
= - 26.31 kJ
Explanation:
we know that number of moles is calculated as
= 0.00476 mol
Heat absorbed by calorimeter
= 26.87 kJ
Enthalpy of combustion
= - 55290.12 kJ/mol
Negative sign shows that the heat is released
The balanced reaction
ΔHc = ΔU + Δng (RT)
-55290.12 = ΔU + (12 - 12) *(RT)
= - 26.31 kJ
Answer:
h = 0.697 [m]
Explanation:
To solve this problem we must use the energy conservation theorem, where it tells us that kinetic energy is converted to potential energy or vice versa.
where:
Ekinet = kinetic energy [J]
Epot = potential energy [J]