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Elenna [48]
2 years ago
9

In the diagram below, point A is southwest of point B. Jaleh walks for 400 seconds along path 1, going from point A to point B.

She then runs for 100 seconds from point B back to point A, following path 3. What is Jaleh's velocity for the first part of her trip? (Remember that velocity is calculated using displacement and time.)
A. 0 m/s

B. 0.5 m/s northeast

C. 1.4 m/s southwest

D. 1 m/s northeast

Physics
2 answers:
Maslowich2 years ago
6 0
The answer is indeed A according to my calculations
timama [110]2 years ago
4 0

Answer:

C

Explanation:

velocity = displacement (m) / change of time (s)

velocity = (400 + 300) / (100 + 400)

velocity = 1.4 m/s

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A rocket, weighing 4.36 x 10^4 N, has an engine that provides an upward force of 8.90 x 10^5 N. It reaches a maximum speed of 86
Pavel [41]

The net force on the rocket is  846400 N.

Answer:

Explanation:

It is known that weight is the influence of gravitational force acting on any mass of the object. So in the present case, the weighing force given is equal to the gravitational force acting on the rocket. Thus, the gravitational force will be acting towards downward direction. But an upward force is required by the rocket for thrusting purpose and that force is given as upward force. So the net force acting on the rocket is the vector addition of all the forces acting on the rocket. As in this case, only upward and downward force is acting on the rocket. The vector addition will be equal to subtraction of downward acting gravitational force from upward force or force provided by engine.

Net force = Engine force - Gravitational force = 890000-43600=846400 N

So the net force acting on the rocket is 846400 N.

8 0
3 years ago
60 POINTS ANSWER CORRECTLY
ohaa [14]

Answer:

C ) 1.53

Explanation:

The critical angle of a material is given by the formula

sin c = \frac{1}{n}

where

c is the critical angle

n is the refractive index

This formula is valid if the second medium is air (which is the case of the problem).

In this problem, we know the critical angle:

c=40.8^{\circ}

Therefore we can rearrange the equation to find the refractive index:

n=\frac{1}{sin c}=\frac{1}{sin 40.8^{\circ}}=1.53

5 0
4 years ago
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Name two ways that friction is harmful and two ways that friction is helpful to you when riding a bicycle
lawyer [7]
<u>Harmful</u><u />

-causes heat; if it's not used correctly, it can cause injury
-when falling, the friction between your knee/leg and the ground can cause scrapes
<u>
</u>
<u>Helpful</u><u />

-helps stop the bike, the brakes rub against the tire which slows it down to a stop
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6 0
3 years ago
Discuss the phase change condition due to reflection of light from a surface. Summarize equations of interference for thin film.
Dmitrij [34]

Answer:

if this surface has a higher index than in the medium where the light travels, the reflected wave has a phase change of 180º

Explanation:

When a ray of light falls on a surface if this surface has a higher index than in the medium where the light travels, the reflected wave has a phase change of 180º this can be explained by Newton's third law, the light when arriving pushes the atoms of the medium that is more dense, and these atoms respond with a force of equal magnitude, but in the opposite direction.

When the fractional index is lower than that of the medium where the reflacted beam travels, notice a change in phase.

Also, when light penetrates the medium, it modifies its wavelength

              λ = λ₀ / n

We take these two aspects into account, the condition for contributory interference is

            d sin θ = (m + 1/2) λ

for destructive interference we have

            d sin θ = m λ

in general this phenomenon is observed at 90º

           2 d = (m +1/2) λ° / n

          2nd = (m + ½) λ₀

5 0
3 years ago
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Alik [6]

Answer:

The answer is in 3 point

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3 0
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